Lecture_27 - Lecture 27 Page 4 The Common-Base Amplifier(Continued Solve first for the input resistance R i by first finding the intermediate

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EE 310 Lecture 27 The Common-Collector Amplifier Sketch a model of this circuit: r r o B C v be g m v be or i b i b E E Lecture 27 Page 1

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Ready for Analysis Find v o in terms of i b : Express i b in terms of v o and v b : Express v b in terms of vi and R i : Combine and solve for v o / v i : EE 310 Lecture 27 Lecture 27 Page 2
Emitter-Follower Output Resistance Solve for the output resistance, R o . r π = 3.28 kΩ, β = 100, r o = 100 kΩ, R E = 400 Ω, R S = 500 Ω, R 1 = R 2 = 50 kΩ Simplify by defining an intermediate current, i x ' and then finding R o in terms of r o , R E , and v x / i x ' : Now find i x ' in terms of i b : Then find v x / i x ' : Finally, find R o : EE 310 Lecture 27 Lecture 27 Page 3

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The Common-Base Amplifier r r o B C v be g m v be or i b i b E E Sketch a model of the amplifier circuit: Rearrange the model: EE 310 Lecture 27

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Unformatted text preview: Lecture 27 Page 4 The Common-Base Amplifier (Continued) Solve first for the input resistance, R i by first finding the intermediate resistance R ie : R i R ie Now combine R ie and R E in parallel to find R i : EE 310 Lecture 27 Lecture 27 Page 5 The Common-Base Amplifier (Continued) Now solve for the voltage gain. First express v o as a function of v π : R i Next express V π as a function of v i : Finally, divide to get v o / v i : EE 310 Lecture 27 Lecture 27 Page 6 Summary A single transistor is seldom enough to build an amplifier with reasonable characteristics: EE 310 Lecture 27 Lecture 27 Page 7...
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This note was uploaded on 10/12/2010 for the course E E 310 at Pennsylvania State University, University Park.

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Lecture_27 - Lecture 27 Page 4 The Common-Base Amplifier(Continued Solve first for the input resistance R i by first finding the intermediate

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