Lecture_32

Lecture_32 - To synthesize v O = A v I + B Determine A and...

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EE 310 Lecture 32 The Op-Amp Differentiator Express v O as a function of v I : Lecture 32 Page 1
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Differentiator Example t v I t v O t v O Let v I ( t ) be a square wave as shown. Sketch v O ( t ). Assume that v C (0) = 0V A T What can we say about the response of a differentiator that uses a non-ideal op amp ? EE 310 Lecture 32 Lecture 32 Page 2
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Synthesis of Arbitrary Linear Functions Using Op Amps Input Signal Specifications: v I T 3 V +25 °C 6 V +125 °C Output Signal Specifications: v O T 0 V 0 °C 10 V +100 °C Op-Amp Circuit v I v I T T v O EE 310 Lecture 32 Lecture 32 Page 3
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Scaling and Offsetting Find the transfer function of the following general op-amp scaling circuit: EE 310 Lecture 32 Lecture 32 Page 4
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Scaling and Offsetting (Continued) Now find the resistor values for the temperature transducer problem, v O = 3.33 v I − 7.5 V: EE 310 Lecture 32 Lecture 32 Page 5
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Generalizing the Procedure
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Unformatted text preview: To synthesize v O = A v I + B Determine A and B from your requirements 1. Connect to v 1 : V + if B is negative V if B is positive 2. Choose R 2 and R 1 so that v O = B when v I = 0 3. If A is negative: Connect v I to the v 2 input and ground the v 3 input Choose R 3 for the correct gain value, A = R 2 / R 3 4. If A is positive: Connect v I to the v 3 input Calculate the gain as A = (1 + R 2 / R 1 ) a) If the calculated gain is too small then ground the v 2 terminal and choose R 3 to get the desired gain value, A = [1 + R 2 /( R 1 || R 3 )] b) If the calculated gain A = (1 + R 2 / R 1 ) is too large, remove R 3 and use a voltage divider between the input signal and the v 3 input terminal. 5. EE 310 Lecture 32 Lecture 32 Page 6...
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Lecture_32 - To synthesize v O = A v I + B Determine A and...

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