hw7.a - . 3 , for 1 . 3 x < 1 . 7 . 8 , for 1 ....

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 12.4 Question 6 Given the probabilty mass function x P ( X = x ) - 1 0 . 1 - 0 . 5 0 . 2 0 . 1 0 . 1 0 . 5 0 . 25 1 0 . 35 we can determine the distribution F ( x ) = 0 , for x < - 1 0 . 1 , for - 1 x < - 0 . 5 0 . 3 , for - 0 . 5 x < 0 . 1 0 . 4 , for 0 . 1 x < 0 . 5 0 . 65 , for 0 . 5 x < 1 1 , for x 1 and graph it Chapter 12.4 Question 8 Given the distribution F ( x ) = 0 , for x < 0 0 . 1 , for 0 x < 1 . 3
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: . 3 , for 1 . 3 x &lt; 1 . 7 . 8 , for 1 . 7 x &lt; 1 . 9 . 9 , for 1 . 9 x &lt; 2 1 , for x 2 we can deduce the probability mass function 1 x P ( X = x ) . 1 1 . 3 . 2 1 . 7 . 5 1 . 9 . 1 2 . 1 2...
View Full Document

Page1 / 2

hw7.a - . 3 , for 1 . 3 x &amp;amp;lt; 1 . 7 . 8 , for 1 ....

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online