EE 332 Lesson 0723

# EE 332 Lesson 0723 - 7/23/2010 CE AMPLIFIER (INVERTING)...

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7/23/2010 1 ©UW EE TC Chen Microelectronic Circuit Design Jaeger/Blalock EE 332 DEVICES AND CIRCUITS II WEEK 5 ©UW EE TC Chen Microelectronic Circuit Design Jaeger/Blalock CE AMPLIFIER (INVERTING) WITHOUT BYPASS CAPACITOR/ GAIN R s v S C1 R 2 R 1 R C R E Q1 C2 V CC R L v o Step 1: DC analysis No change from with bypass capacitor Step 2: Small Signal Parameter No change from with bypass capacitor 40 2.5 54.6 m m A CE O C g mS rk g VV I 11 ©UW EE TC Chen Microelectronic Circuit Design Jaeger/Blalock CE AMPLIFIER (INVERTING) WITHOUT BYPASS CAPACITOR/ SMALL SIGNAL MODEL R s v S C1 R 2 R 1 R C R E Q1 C2 V CC R L v o v o v s R B R C R L r r o g m v be v be R s R E 12 ©UW EE TC Chen Microelectronic Circuit Design Jaeger/Blalock CE AMPLIFIER (INVERTING) WITHOUT BYPASS CAPACITOR/ GAIN v o v s R B R C R L r r o g m v be v be R s R E Step 3: Small Signal Equivalent Circuit () 1 1 1 1 ( ) ( ) e b e o e m b e Eo o e m b m o E o v v v v v g v v R r r v v g v g r r R r r   2 node (v e , v o ) equations: ( ) 0 1 1 1 ( ) ( ) o e o e m b e o LEQ e m o b m o o LEQ v v v v g v v rR v g v v g r r R

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## This note was uploaded on 10/12/2010 for the course IT 23211 taught by Professor Tai during the Summer '10 term at Punjab Engineering College.

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EE 332 Lesson 0723 - 7/23/2010 CE AMPLIFIER (INVERTING)...

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