lesson35

# lesson35 - V B Z V A I R 1 V 1 j ϖ C R 2 I 1 j ϖ L V A V...

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Unformatted text preview: V B Z V A I R 1 V 1- j/ ϖ C R 2 I 1 j ϖ L V A V B V C R 1 V 1 R 2 I 1 j ϖ L I A I B- j/ ϖ C I C Lesson 35 – AC Circuit Analysis III (Sections 8-5 and 8-6) (CLOs 8-4 and 8-5) We did the circuit theorems last lecture and will do Node Voltage and Mesh Currents in this one. It is important to solve several Op-Amp circuits since they will need them later to do active filters. Start by revisiting how to write Node Voltage equations but substitute a Z in place of an R .: Z V V I B A ~ ~ ~- = Then jump directly into an example. The node equations are: 1 2 C 2 B 1 1 2 C 2 1 B 1 C 2 B C C B 2 C B 1 A B B 1 A 1 1 1 1 1 1 I L j R V R V R V R V C j R R V I L j V R V V V C j V R V V R V V V V V ~ ) ( ~ ) ( ~ ~ ) ( ~ ) ( ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ = ϖ + +- =- ϖ + + =- ϖ- +- → = ϖ-- +- +- → = These can then be solved using one of several methods to find B V ~ and C V ~ . Next, discuss Mesh Equation analysis and use the same circuit: 2 1 2 B A 1 C 1 B 1 A 1 C B 2 C B A B B B A 1 C A 1 A R I L j R I I R I V I R I I I L j I R I I I I I I I R I I V I C j C j C j C j C j C j ~ ) ( ~ ) (...
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lesson35 - V B Z V A I R 1 V 1 j ϖ C R 2 I 1 j ϖ L V A V...

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