HW3 - ECE 20"" 1’5 Due 09.115119 ‘ 22/7 1 Use...

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Unformatted text preview: ECE 20"" 1’5 Due: 09.115119 ‘ 22/7 1. Use the nodevvoltage method to find vain the circuit shown in Fig. 1. : 17w 4.. .'_+_'- —_‘~’;:75 VA 0 U?» flCZO +50 [40 a 3'.VL'751“_%+M20 ' f so no em I‘m—b up 300 900F135. 1 7; z)‘ 75 _|__ __".. __ __’°. : (9 1‘...— zoom to 4 2.00 560) v7; w 300 y; _ I)“; {0: 5 J; 0r 2. Use the node~voltage method mind the 01:31 power provided by the independent I I 1 LS v 3. Use the mesh-current method to find the current of each independent voltage 3013c: inthecircuitshowninFig,3. [0003}: —|[() 41—10(L-LA 1. BCLP I?) 5'; T. I’ll-t : D (IO-Ira???“ F a)? 4 [OI—3 : MHZ" Li '3'" + 3U; ‘ 1.1+ {Mir}ij +704, 2,1“ = O *3i,1—( 3 +435? 2J1: ‘ JZI; : '70 I so I ’31. 1- 0.752. ' ill-5 '— ~55 Holt r r117, Jr ((0 +9 +12) :0 r ‘ — ’“ +~ I :0 ' . (Dir 121; 23 5 Fig.3 I O I b 1‘ a ' ' O I : "2— ' I I 4. Use the mesh-current method to find the total power dissipated in the circuit shown in Fig. 4. Fig. 4 5. The variébie dc voitage source in the circuit shown in Fig. 5 is adjusted so that i0 = 0 Determine the value of Kit . F t 203 25!}. 6. Probiem 3.17 in the textbook (page 16). 7. Probiem 3.23 in the textbook (page 117). 8. Problem 3.51 in the textbook (page 121). ...
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HW3 - ECE 20"" 1’5 Due 09.115119 ‘ 22/7 1 Use...

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