HW1 - Homework 1 and has 100 times the amount of potassium...

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Homework 1 1 Problem 1 . Given : The beaker below is divided by a semi-permeable membrane that is only permeable to K+ and has 100 times the amount of potassium acetate on the left side than on the right side. (A) Under these conditions, what will the voltage of the right side of the beaker be relative to the left side? You now perform an experiment where you want to set (clamp) the voltage of the right side at a specific value. In this particular experiment we are going to clamp the right side of the beaker at 17 mV relative to the left side of the beaker. You do this by putting two electrodes in the right side of the beaker (see figure to left). One electrode measures the voltage. This value is fed back to electronic equipment, which then calculates how much current must be injected through the second “clamping” electrode to hold the right side voltage at 17 mV relative to the left side. Before beginning the experiment, the right side is sitting at the voltage you calculated in part (A). You then turn the voltage clamp on and within a millisecond the clamp is generating current which clamps the right side's voltage at 17 mv. (B)
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This note was uploaded on 10/12/2010 for the course NPB 100 taught by Professor Chapman during the Winter '08 term at UC Davis.

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HW1 - Homework 1 and has 100 times the amount of potassium...

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