{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

SAmple_exam2B - Part 1(21 points correct elimination 4...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Part 1: (21 points, correct elimination 4 points, incorrect elimination –21 points). The following properties apply to the circuit shown below. ¾ Cell F has no spontaneous activity ¾ Cell F does NOT habituate ¾ Cell F has post-inhibitory rebound (through the cell E to Cell F synapse) ¾ Cell E has spontaneous activity ¾ Cell E habituates through the Cell D to Cell E synapse ¾ This habituation is through the D Æ E synapse so the longer D is on the less effective Cell E’s excitatory neurotransmitter receptor becomes ¾ Cell E does NOT have has post-inhibitory rebound ¾ Cell F’s inhibition onto cell E can completely shut down cell E including inhibiting and turning off spontaneous spikes ¾ Cell E’s spontaneous firing is at a low enough rate that it cannot counteract Cell D Æ F excitation ¾ D Æ F is a shorter length than D Æ E Which of the following can be the activity pattern of the circuit, when D fires as shown in the panels. Excitation Inhibition LEGEND (1) (2) (3) (4) (5) (6)
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon