HW1 solutions - (depth = 12.75) 0.75(69.3) + 0.25 (69.8) =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
(b) Middle half Low Quartile High Quartile Median Maximum Minimum Outliers ( c) Median resits the influence of outliers. But is that good? Is it the mean (average in long-run) Or the median (50 percentile) that one wants? #1 DESCRIPTIVE STATISTICS (a)Steam-and-leaf (b)- ( c) Frequency (d) Fraction < 50 = 34%; Fractions 60 = 54% (e) Median 60.8 (depth = 51/2 = 25.5) (f) Quartiles 0.75(45.9) + 0.25 (44.6) = 45.6
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: (depth = 12.75) 0.75(69.3) + 0.25 (69.8) = 69.4 Interquartile range = 23.8 Range 27.1 to 94.6 Forths 45.9 and 69.3 (depth = (50+2)/4 = 13) (f) Forths versus quartiles (g) Forth spread 69.3 45.9 = 23.4 (h) Histogram #2. average 58.54, s = 16.5 #3 Boxplots #4 Discuss Vapor Data (i)Note trend with time of day = temperature (ii) Spread relative constant (ii) Note severe outliers at 6 am. WHY?...
View Full Document

This note was uploaded on 10/13/2010 for the course CEE 3040 at Cornell University (Engineering School).

Ask a homework question - tutors are online