ch17-sol - Physics 102 Chapter 17 Homework Solution 17.1...

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Physics 102 Chapter 17 Homework Solution 17.1 The charge that moves past the cross section is ( ) Q It Δ , and the number of electrons is ( ) () 3 20 19 80.0 10 C s 10.0 mi n6 0 . 0 smin 3.00 10 electron s 1 ±² ± ² ± .60 10 C It Q n ee Δ Δ == × × × ⎡⎤ ⎣⎦ The negatively charged electrons move in the direction opposite to the conventional current flow. 17.4 ( ) QIt Δ=Δ and the number of electrons is ( )( ) 6 14 -19 60. 01 0 Cs1 .00 s 3.75 10 electron s 1.60 10 C Q n × Δ Δ = = × × 17.5 The period of the electron in its orbit is 2 T rv π = , and the current represented by the orbiting electron is ( ) 61 9 3 11 2 2.19 10 m s 1.60 10 C 1.05 10 C s 1.05 mA 25 . 29 10 m ev e Q I tT r Δ = Δ ×× × × = 17.10 120 V 0.500 A5 0 0 240 V I R Δ = = Ω
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17.11 () ( ) 6 max 80 10 A VI R Δ== × 5 4. 01 0 R Ω R Thus, if , 32 V V Δ= 2 000 R and if , 0.16 V V 17.13 From L R A ρ = , we obtain 2 4 d L A R π == , or ( ) 82 4 45. 61 0 m 2 . 0 m 4 1. 71 m0 . 17 mm 0.050 L d R ππ −− ×Ω × = ×= Ω 17.14 (extra) ( )( ) 8 2 2 3 41. 0 m 1 5 m 0.31 4 1.024 10 m LL R Ad ρρ = = Ω × 17.15 (a) 12 V 30 0.40 A V R I Δ (b) From, L R A = , 2 2 4 0.40 10 m 3.2 m RA L ⎡⎤ Ω× ⋅⎢ ⎣⎦ = × Ω
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17.31 600 W 5.00 A 120 V I V == = Δ P and 24.0 V R I Δ = Ω 17.32 (a) The energy used by a 100-W bulb in 24 h is ( )( ) ( )( ) 100 W2 4 h0 . 100 kW 24 h2 . 4 kW h Et =⋅ Δ= = = P () and the cost of this energy, at a rate of $0.12 per kilowatt-hour is
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ch17-sol - Physics 102 Chapter 17 Homework Solution 17.1...

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