ch20-sol - Problem Solutions 20.1 The magnetic flux through...

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Problem Solutions 20.1 The magnetic flux through the area enclosed by the loop is ( ) () ( ) 2 2 22 cos cos0 0.30 T0 . 25 m5 . 91 0 Tm B BA B r θπ π ⎡⎤ Φ= = °= = × ⎣⎦ 20.2 The magnetic flux through the loop is given by B BA θ Φ = where B is the magnitude of the magnetic field, A is the area enclosed by the loop, and is the angle the magnetic field makes with the normal to the plane of the loop. Thus, 7 2 1.00 -2 52 10 m 5.00 10 T2 0 . 0 cm 1 cm B BA 2 10 Tm c o s θθ −− × ⎛⎞ = ⎢⎥ ⎜⎟ ⎝⎠ = × (a) When B is perpendicular to the plane of the loop, JG 0 = ° and 72 B × (b) If ( ) 7 28 30. 0, then 1.00 10 T m cos30. 08 . 66 10 B Φ = × ° = × 2 (c) If ( ) 90. 0, then cos90. 00 B Φ = × ° = 20.3 The magnetic flux through the loop is given by B BA Φ = where B is the magnitude of the magnetic field, A is the area enclosed by the loop, and is the angle the magnetic field makes with the normal to the plane of the loop. Thus, ( ) 2 1 2 0.300 .
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This note was uploaded on 10/13/2010 for the course PHYSICS 102 taught by Professor Abdulrazzaq during the Fall '08 term at West Virginia State University.

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ch20-sol - Problem Solutions 20.1 The magnetic flux through...

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