4 - Phys102 Lecture 4 Phys102 Lecture 4 - 1 Gausss Law Key...

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Phys102 Lecture 4 Gauss’s Law Key Points Electric Flux Gauss’s Law Applications of Gauss’s Law References SFU Ed: 22-1,2,3. 6 th Ed: 16-10,+. Phys102 Lecture 4 - 1
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Electric flux: Electric flux through an area is proportional to the total number of field lines crossing the area. Electric Flux The direction of area if defined as the normal direction.
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Example 22-1: Electric flux. Calculate the electric flux through the rectangle shown. The rectangle is 10 cm by 20 cm, the electric field is uniform at 200 N/C, and the angle θ is 30° .
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Flux through a closed surface: in (-) out (+) (Just a new notation)
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The total flux through a closed surface is equal to the charge enclosed divided by e 0 : This can be used to find the electric field in situations with a high degree of symmetry. 22- 2 Gauss’s Law
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22- 2 Gauss’s Law For a point charge, Therefore, Solving for E gives the result we expect from Coulomb’s law:
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Example 22-3: Spherical conductor. A thin spherical shell of
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This note was uploaded on 10/14/2010 for the course PHYS PHYS 102 taught by Professor Michaelchen during the Fall '10 term at Simon Fraser.

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4 - Phys102 Lecture 4 Phys102 Lecture 4 - 1 Gausss Law Key...

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