# 4 - Phys102 Lecture 4 Phys102 Lecture 4 - 1 Gausss Law Key...

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Phys102 Lecture 4 Gauss’s Law Key Points Electric Flux Gauss’s Law Applications of Gauss’s Law References SFU Ed: 22-1,2,3. 6 th Ed: 16-10,+. Phys102 Lecture 4 - 1

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Electric flux: Electric flux through an area is proportional to the total number of field lines crossing the area. Electric Flux The direction of area if defined as the normal direction.
Example 22-1: Electric flux. Calculate the electric flux through the rectangle shown. The rectangle is 10 cm by 20 cm, the electric field is uniform at 200 N/C, and the angle θ is 30° .

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Flux through a closed surface: in (-) out (+) (Just a new notation)
The total flux through a closed surface is equal to the charge enclosed divided by e 0 : This can be used to find the electric field in situations with a high degree of symmetry. 22- 2 Gauss’s Law

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22- 2 Gauss’s Law For a point charge, Therefore, Solving for E gives the result we expect from Coulomb’s law:
Example 22-3: Spherical conductor. A thin spherical shell of

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## This note was uploaded on 10/14/2010 for the course PHYS PHYS 102 taught by Professor Michaelchen during the Fall '10 term at Simon Fraser.

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4 - Phys102 Lecture 4 Phys102 Lecture 4 - 1 Gausss Law Key...

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