Unformatted text preview: from the surface of the water to the top of the we : The sound wave propaga es a he speed of sound and s mo on s governed by dz = a dt The so u on for he pos on of he wave fron s z(t) = s  at The wave fron reaches he surface when z = 0 wherefore t2 = s a z(0) = s 96 So, the total time, , is = t1 + t2 = CHAPTER 2. PARTICLE KINEMATICS 2s s + g a We are given a = 1160 ft/sec and s = 500 ft. Thus, the time is = 2(500 ft) 32.174 ft/sec
2 + 500 ft = 5.575 sec + 0.431 sec = 6.0 sec 1160 ft/sec Note that only 7.2% of the total time corresponds to the sound wave traveling from the surface of the water to the top of the well....
View
Full
Document
This note was uploaded on 10/15/2010 for the course AME 301 at USC.
 '06
 Shiflett

Click to edit the document details