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Unformatted text preview: x 2 ) 3 / 2 ² = ∓ R 2 ( R 2 − x 2 ) 3 / 2 So, the radius of curvature is ρ = 1 + x 2 / D R 2 − x 2 i 3 / 2 ∓ R 2 / ( R 2 − x 2 ) 3 / 2 = ∓ R 3 / D R 2 − x 2 i 3 / 2 R 2 / ( R 2 − x 2 ) 3 / 2 = ∓ R Note that ρ is negative on the upper half of the circle, which has concave curvature relative to the x axis. By contrast, ρ is positive on the lower part of the circle, which has convex curvature relative to the x axis....
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This note was uploaded on 10/15/2010 for the course AME 301 at USC.
 '06
 Shiflett

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