Homework02 - Rodriguez Brandon – Homework 2 – Due 11:00 am – Inst Andrew J Rader 1 This print-out should have 10 questions Multiple-choice

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Unformatted text preview: Rodriguez, Brandon – Homework 2 – Due: Aug 29 2006, 11:00 am – Inst: Andrew J Rader 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Please notice that for your homework to be considered towards your grade, it needs to be submitted one hour before the corresponding recitation starts. Work submitted after this time, but before the DUE DATE on top of this page, will be accepted but not graded. PLEASE REMEMBER THAT YOU MUST CARRY OUT YOUR CALCULA- TIONS TO AT LEAST THREE SIGNIFI- CANT FIGURES. YOUR ANSWER MUST BE WITHIN ONE PERCENT OF THE CORRECT RESULT TO BE MARKED AS CORRECT BY THE SERVER. 001 (part 1 of 1) 5 points A sphere is charged with electrons to- 5 × 10- 6 C. The charge of an electron is- 1 . 6 × 10- 19 C. How many electrons are there on the sphere? Correct answer: 3 . 125 × 10 13 . Explanation: Let : q =- 5 × 10- 6 C and q e =- 1 . 6 × 10- 19 C . The total charge is q = nq e n = q q e =- 5 × 10- 6 C- 1 . 6 × 10- 19 C = 3 . 125 × 10 13 . keywords: 002 (part 1 of 1) 5 points Four point charges, each of magnitude 16 . 75 μ C, are placed at the corners of a square 52 . 1 cm on a side. The value of Coulomb’s constant is 8 . 98755 × 10 9 N · m 2 / C 2 . If three of the charges are positive and one is negative, find the magnitude of the force experienced by the negative charge. Correct answer: 17 . 7822 N. Explanation: Let : k e = 8 . 98755 × 10 9 N · m 2 / C 2 , d = 52 . 1 cm = 0 . 521 m , and Q = 16 . 75 μ C = 1 . 675 × 10- 5 C . F 24 F 34 F 14 + 3 + 1 + 2- 4 The forces are F 34 = F 24 = k e Q 2 d 2 = ( 8 . 98755 × 10 9 N · m 2 / C 2 ) × ( 1 . 675 × 10- 5 C ) 2 (0 . 521 m) 2 = 9 . 28957 N F 14 = k e Q 2 ( √ 2 d ) 2 = 1 2 k e Q 2 d 2 = 1 2 F 34 The vector sum of F 24 and F 34 is in the same direction as F 14 , so F = F 14 + q F 34 2 + F 24 2 = 1 2 F 34 + q 2 F 34 2 = µ 1 2 + √ 2 ¶ F 34 = µ 1 2 + √ 2 ¶ (9 . 28957 N) = 17 . 7822 N ....
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This note was uploaded on 10/18/2010 for the course PHYSICS 251 taught by Professor Pedon during the Spring '08 term at IUPUI.

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Homework02 - Rodriguez Brandon – Homework 2 – Due 11:00 am – Inst Andrew J Rader 1 This print-out should have 10 questions Multiple-choice

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