This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: Rodriguez, Brandon – Homework 10 – Due: Sep 26 2006, 11:00 am – Inst: Andrew J Rader 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Please notice that for your homework to be considered towards your grade, it needs to be submitted one hour before the corresponding recitation starts. Work submitted after this time, but before the DUE DATE on top of this page, will be accepted but not graded. PLEASE REMEMBER THAT YOU MUST CARRY OUT YOUR CALCULA- TIONS TO AT LEAST THREE SIGNIFI- CANT FIGURES. YOUR ANSWER MUST BE WITHIN ONE PERCENT OF THE CORRECT RESULT TO BE MARKED AS CORRECT BY THE SERVER. 001 (part 1 of 1) 5 points The emf of a battery is E = 19 V . When the battery delivers a current of 0 . 6 A to a load, the potential difference between the terminals of the battery is 17 V volts. Find the internal resistance of the battery. Correct answer: 3 . 33333 Ω. Explanation: Given : E = 19 V , V load = 17 V , and I = 0 . 6 A . The potential difference across the internal resistance is E - V load , so the internal resis- tance is given by r = E - V load I = 19 V- 17 V . 6 A = 3 . 33333 Ω . keywords: 002 (part 1 of 4) 5 points A battery has an emf of 12 V and an inter- nal resistance of 0 . 18 Ω. Its terminals are connected to a load resistance of 2 Ω. Find the current in the circuit. Correct answer: 5 . 50459 A. Explanation: Let : E = 12 V , R = 2 Ω , and r = 0 . 18 Ω . The total resistance is R + r , so I = E R + r = 12 V 2 Ω + 0 . 18 Ω = 5 . 50459 A . 003 (part 2 of 4) 4 points Calculate the terminal voltage of the battery. Correct answer: 11 . 0092 V....
View Full Document
This note was uploaded on 10/18/2010 for the course PHYSICS 251 taught by Professor Pedon during the Spring '08 term at IUPUI.
- Spring '08