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Unformatted text preview: Rodriguez, Brandon Homework 13 Due: Oct 5 2006, 11:00 am Inst: Andrew J Rader 1 This printout should have 9 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. Please notice that for your homework to be considered towards your grade, it needs to be submitted one hour before the corresponding recitation starts. Work submitted after this time, but before the DUE DATE on top of this page, will be accepted but not graded. PLEASE REMEMBER THAT YOU MUST CARRY OUT YOUR CALCULA TIONS TO AT LEAST THREE SIGNIFI CANT FIGURES. YOUR ANSWER MUST BE WITHIN ONE PERCENT OF THE CORRECT RESULT TO BE MARKED AS CORRECT BY THE SERVER. 001 (part 1 of 1) 8 points The segment of wire in the figure carries a current of 8 A, where the radius of the circular arc is 5 cm. The permeability of free space is 1 . 25664 10 6 T m / A . 8 A 5 c m O Determine the magnitude of the magnetic field at point O , the origin of the arc. Correct answer: 25 . 1327 T. Explanation: Let : I = 8 A and R = 5 cm = 0 . 05 m . For the straight sections d ~s r = 0. The quarter circle makes onefourth the field of a full loop B = I 8 R into the paper. Or, you can use the equation B = o I 4 , where = 2 . Thus the magnetic field is B = I 8 R , = (1 . 25664 10 6 T m / A)(8 A) 8(0 . 05 m) = 25 . 1327 T , into the paper . keywords: 002 (part 1 of 1) 8 points A long, thin conductor carries a current of 13 . 8 A. At what distance from the conductor is the magnitude of the resulting magnetic field 9 . 62 10 5 T? Correct answer: 2 . 86902 cm. Explanation: Let : = 1 . 25664 10 6 N / A 2 , B = 9 . 62 10 5 T , and I = 13 . 8 A . By the BiotSavart Law, B = I 2 r r = I 2 B = (1 . 25664 10 6 N / A 2 )(13 . 8 A) 2 (9 . 62 10 5 T) = 0 . 0286902 m = 2 . 86902 cm . keywords: 003 (part 1 of 2) 8 points A conductor in the shape of a square, whose sides are of length 0 . 76 m, carries a clockwise 13 A current as shown in the figure below. Rodriguez, Brandon Homework 13 Due: Oct 5 2006, 11:00 am Inst: Andrew J Rader 2 . 76 m 13 A P What is the magnitude of the magnetic field at point P (at the center of the square loop) due to the current in the wire?...
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This note was uploaded on 10/18/2010 for the course PHYSICS 251 taught by Professor Pedon during the Spring '08 term at IUPUI.
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