homework16

# homework16 - Rodriguez Brandon Homework 16 Due 11:00 am...

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Rodriguez, Brandon – Homework 16 – Due: Oct 17 2006, 11:00 am – Inst: Andrew J Rader 2 keywords: 002 (part 1 of 2) 4 points A 0 . 0568 A current is charging a capacitor that has square plates, 5 . 59 cm on a side. The permitivity of free space is 8 . 85419 × 10 - 12 C 2 / N m 2 . If the plate separation is 2 . 33 mm find the time rate of change of electric flux between the plates. Correct answer: 6 . 41504 × 10 9 V m / s. Explanation: Let : I = 0 . 0568 A and ² 0 = 8 . 85419 × 10 - 12 C 2 / N m 2 . The electric field between the two plates is E = Q ² 0 A . Then the rate of change of electric flux be- tween the plates is d Φ E dt = d dt ( E A ) = I ² 0 = 0 . 0568 A 8 . 85419 × 10 - 12 C 2 / N m 2 = 6 . 41504 × 10 9 V m / s . 003 (part 2 of 2) 4 points Find the displacement current between the plates. Correct answer: 0 . 0568 A. Explanation: The displacement current is I d = ² 0 d Φ E dt = I = 0 . 0568 A . keywords: 004 (part 1 of 2) 4 points A straight, horizontal rod slides along parallel conducting rails at an angle with the horizon- tal, as shown below. The rails are connected at the bottom by a horizontal rail so that the rod and rails forms a closed rectangular loop.
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