Unformatted text preview: CORRECT RESULT TO BE MARKED AS CORRECT BY THE SERVER. 001 (part 1 oF 1) 0 points A 2 . 6 kg particle starts From rest and moves a distance oF 2 . 1 m in 1 . 6 s under the action oF a single, constant Force. ±ind the magnitude oF the Force. Correct answer: 4 . 26562 N. Explanation: Basic Concept: v f = v i + a t v 2 f = v 2 i + 2 a x Solution: Since v i = 0, v f 2 = 2 a x a 2 t 2 = 2 a x a 2 t 22 a x = 0 a ( a t 22 x ) = 0 a = 2 x t 2 The solution a = 0 must be ignored. ±rom Newton’s second law, the Force on the particle is F = m a = 2 m x t 2 = 2 (2 . 6 kg) (2 . 1 m) 1 . 6 s 2 = 4 . 26562 N keywords:...
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 Spring '08
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 Mass, Work, General Relativity, Andrew J Rader

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