homework17_testday

homework17_testday - CORRECT RESULT TO BE MARKED AS CORRECT...

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Rodriguez, Brandon – Homework 17 – Due: Oct 19 2006, 11:00 am – Inst: Andrew J Rader 1 This print-out should have 1 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. Please notice that For your homework to be considered towards your grade, it needs to be submitted one hour beFore the corresponding recitation starts. Work submitted aFter this time, but beFore the DUE DATE on top oF this page, will be accepted but not graded. PLEASE REMEMBER THAT YOU MUST CARRY OUT YOUR CALCULA- TIONS TO AT LEAST THREE SIGNI±I- CANT ±IGURES. YOUR ANSWER MUST BE WITHIN ONE PERCENT O± THE
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Unformatted text preview: CORRECT RESULT TO BE MARKED AS CORRECT BY THE SERVER. 001 (part 1 oF 1) 0 points A 2 . 6 kg particle starts From rest and moves a distance oF 2 . 1 m in 1 . 6 s under the action oF a single, constant Force. ind the magnitude oF the Force. Correct answer: 4 . 26562 N. Explanation: Basic Concept: v f = v i + a t v 2 f = v 2 i + 2 a x Solution: Since v i = 0, v f 2 = 2 a x a 2 t 2 = 2 a x a 2 t 2-2 a x = 0 a ( a t 2-2 x ) = 0 a = 2 x t 2 The solution a = 0 must be ignored. rom Newtons second law, the Force on the particle is F = m a = 2 m x t 2 = 2 (2 . 6 kg) (2 . 1 m) 1 . 6 s 2 = 4 . 26562 N keywords:...
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This note was uploaded on 10/18/2010 for the course PHYSICS 251 taught by Professor Pedon during the Spring '08 term at IUPUI.

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