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Unformatted text preview: Rodriguez, Brandon Homework 18 Due: Oct 24 2006, 11:00 am Inst: Andrew J Rader 1 This printout should have 13 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. Please notice that for your homework to be considered towards your grade, it needs to be submitted one hour before the corresponding recitation starts. Work submitted after this time, but before the DUE DATE on top of this page, will be accepted but not graded. PLEASE REMEMBER THAT YOU MUST CARRY OUT YOUR CALCULA TIONS TO AT LEAST THREE SIGNIFI CANT FIGURES. YOUR ANSWER MUST BE WITHIN ONE PERCENT OF THE CORRECT RESULT TO BE MARKED AS CORRECT BY THE SERVER. 001 (part 1 of 3) 4 points A 58 mA current is carried by a uniformly wound aircore solenoid with 647 turns as shown in the figure below. The permeability of free space is 1 . 25664 10 6 N / A 2 . 5 8 m A 13 . 4 mm 7 . 85 cm Compute the magnetic field inside the solenoid. Correct answer: 0 . 000600721 T. Explanation: Let : N = 647 , = 7 . 85 cm , I = 58 mA , and = 1 . 25664 10 6 N / A 2 . I d The magnetic field inside the solenoid is B = n I = N I = (1 . 25664 10 6 N / A 2 ) 647 . 0785 m (0 . 058 A) = . 000600721 T . 002 (part 2 of 3) 4 points Compute the magnetic flux through each turn. Correct answer: 8 . 47173 10 8 Wb. Explanation: Let : B = 0 . 000600721 T , and d = 13 . 4 mm = 0 . 0134 m . The magnetic flux through each turn is = B A = B 4 d 2 = (0 . 000600721 T) 4 (0 . 0134 m) 2 = 8 . 47173 10 8 Wb . 003 (part 3 of 3) 3 points Compute the inductance of the solenoid. Correct answer: 0 . 945036 mH. Explanation: The inductance of the solenoid is L = N I = (647)(8 . 47173 10 8 Wb) . 058 A = . 945036 mH . Rodriguez, Brandon Homework 18 Due: Oct 24 2006, 11:00 am Inst: Andrew J Rader 2 keywords: 004 (part 1 of 2) 4 points...
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