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Unformatted text preview: Rodriguez, Brandon Homework 22 Due: Nov 7 2006, 11:00 am Inst: Andrew J Rader 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. Please notice that for your homework to be considered towards your grade, it needs to be submitted one hour before the corresponding recitation starts. Work submitted after this time, but before the DUE DATE on top of this page, will be accepted but not graded. PLEASE REMEMBER THAT YOU MUST CARRY OUT YOUR CALCULA- TIONS TO AT LEAST THREE SIGNIFI- CANT FIGURES. YOUR ANSWER MUST BE WITHIN ONE PERCENT OF THE CORRECT RESULT TO BE MARKED AS CORRECT BY THE SERVER. 001 (part 1 of 2) 4 points An object is 20 . 7 cm from the surface of a reflective spherical Christmas-tree ornament 5 . 77 cm in diameter. What is the position of the image? Correct answer:- 1 . 34853 cm. Explanation: 1 p + 1 q = 1 f = 2 R m = h h =- q p Convex Mirror > f > p > f < q < < m < 1 Let : D = 5 . 77 cm and p = 20 . 7 cm . p is positive since it is in front of the mirror and R is negative since it is behind the mir- ror. A spherical Christmas-tree ornament is a convex mirror, so 1 p + 1 q =- 2 | R | . We are given the object distance, p , and can find the radius of curvature from the diameter, | R | = | D | 2 . Inserting these values into the mirror equation and solving for q , we find q =- 1 4 D + 1 p =- 1 4 (5 . 77 cm) + 1 (20 . 7 cm) =- 1 . 34853 cm ....
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This note was uploaded on 10/18/2010 for the course PHYSICS 251 taught by Professor Pedon during the Spring '08 term at IUPUI.
- Spring '08