homework24_testday

homework24_testday - CORRECT RESULT TO BE MARKED AS CORRECT...

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Rodriguez, Brandon – Homework 24 – Due: Nov 14 2006, 11:00 am – Inst: Andrew J Rader 1 This print-out should have 1 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. Please notice that For your homework to be considered towards your grade, it needs to be submitted one hour beFore the corresponding recitation starts. Work submitted aFter this time, but beFore the DUE DATE on top oF this page, will be accepted but not graded. PLEASE REMEMBER THAT YOU MUST CARRY OUT YOUR CALCULA- TIONS TO AT LEAST THREE SIGNI±I- CANT ±IGURES. YOUR ANSWER MUST BE WITHIN ONE PERCENT O± THE
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Unformatted text preview: CORRECT RESULT TO BE MARKED AS CORRECT BY THE SERVER. 001 (part 1 oF 1) 0 points In the fgure shown below, the rod ab , which is 0 . 2 m long, is moved to the right with a speed oF 6 m / s. B v a b l The magnetic feld strength is 1 . 3 T and is directed at right angles to the plane oF the current loop. IF the current loop has a break in it, fnd the induced emF. Correct answer: 1 . 56 V. Explanation: Let : B = 1 . 3 T , = 0 . 2 m , and v = 6 m / s . The induced emF is independent oF whether there is a break or not. The motional emF is E = B v = (1 . 3 T)(0 . 2 m)(6 m / s) = 1 . 56 V . keywords:...
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This note was uploaded on 10/18/2010 for the course PHYSICS 251 taught by Professor Pedon during the Spring '08 term at IUPUI.

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