Unformatted text preview: as illustrated and reside to the left? HO S S MeO OBn H HO S S MeO OBn H 2. Use the curly arrow formalism to illustrate the interconversion of each structure shown below. Note that the sequence that is portrayed accounts for the formation of the minor product in the reaction that was discussed in class. [Notice that overall, the oxidation involves the loss of two electrons and the equivalent of two protons. Conversely, many reductions involve the overall gain of two electrons and the equivalent of two protons.] HO S S MeO OBn H HO S MeO OBn H S HO MeO OBn H S S HO MeO OBn H S S HO MeO OBn H OMe H MeOH HO OMe MeO MeO OBn H a) –H b) –e c) MeOH d) –H...
View Full Document
This note was uploaded on 10/15/2010 for the course CHEM chem 127 taught by Professor Littlerd during the Fall '09 term at UCSB.
- Fall '09