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Fall 2009 Midterm 1

Fall 2009 Midterm 1 - Chemistry 140A Whitcsell Fall Quarter...

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Unformatted text preview: Chemistry 140A Whitcsell Fall Quarter. 2009 First Midterm Exam. Monday October 19. 2009 first name middle last name initial Student ID Number chrade . . "c‘lllC-E'L. _ _ i v',_..——-""' ,/ _ _ _ . __ .f \/ Your answers to this exam are to he mnfr your own work. You may use no written information during this test period other than the six pages ot'this exam. You may no! use the haek of any pages for answers. Up to one week [exactly 163 hours} after your exam is returned you may suhmit it for regrading il'and only il'you have made N0 marks on the exam except for a star t *} ON THIS PAGE next to the numberts) ol'the questionts) you would like regraded. your signature (rend tlt ‘ altm‘e lit-fore signing) To request I'egmding. sign below and check the appropriate hoxcs. your signature I would like the questions marked with a star t *} regraded {check box at right} El It'you feel that we have made an addition error in your score. check the box at the right [I la The corrected ordering ofstability of carbon free radicals is: I] Methyl —‘-- 3° 1- 2“ > I" I] 3" - l“ -- 2" :- methyl E 3" -2“ -l":-methyl [I Methyl ~ I" 2" a" lb VSEPR can be used to predict that the geometry ol‘COg is: D pyramidal El trigonal planar I] tetrahedral [E linear VSEPR can be used to predict that the geometry ol'a carl‘tocalion is: D pyramidal E trigonal planar El tetrahedral El linear F: Id The process ot'combining one s and two p orbitals to make ltydrid atomic orbitals results in: I] Zorbitals l3 3orbitals El slorbitals I:] In orbitals Indicate the strongest acid based upon the Follow pK‘. values: [In [14 5 K? It. D If A l'unctioua] group is: the result of atomic orbital hybridization a collection of atoms that undergoes reactions typical for that group lhe result of molecular orbital hybridization DEED a collection ol'atoms that is unusually stable lg For an equilibrium in which All is 2.7 kcala'mole. the equilibrium ratio is: I] 7:: IX! ltltl:l “1:1 |:| lt)tlt]:l B Your signature [in ink) . __ I‘J 2. Provide bond line fon‘nulzls for possible isomers ril'C'al-lHCI. Use enreu-il'you duplicate in slruelure. neirher will eounl as u correel answer. liaeh answer is worth one poinl and bonus points will be given for Perl‘ee! answers (llmt is. there are fewer than l2 ismnersn—sllowi11g:Ill correctly with no duplieoles will earn you If! pts]. {12 pls) Cl Q] l , ‘ , \ \-/\/\ /\ \ \VI Ql (Ll [ Q1 \l l l \./\/ V -- "\/ /\//\Cl Ql “~— Cl Your signature (in ink] 3. Use the frameworks provide below In show Ncwnmn projcclions for the three staggered coniormations about the C3-C3 homl ol‘ l-chlorohulonc. I I2 pls) Cl C H 3 H H (lilo, H (Ll-I 3 H C H 3 H 3Q H H C! Q i C H 3 ' H H H 4. Provide detailed mechanisms. included appropriate curved arrows showing tlu: movcmcnl ol'nll electrons. for the propagation steps in the free radical] Chlorination oi‘ 2.2-LIimcthylprolmlw. {Flats} 6 CI Cl: —--—D" J'w Your signature (in ink} _—___—_____ __ _ [’mvidc the three hes! resonance structures I'm' the curlnmallc dizmiun (LUV). Shmv all lune-pairs ui'clcclruns. Us: curved arrows to shuw lhc How nl'ulccu'nns converting one ol‘thcsc slructurcs to number { your choice). pts “’2 .. . , O H "'33 o ()D <.____> _‘ _\ u. <_: ___#> n O r; 0 'c' a O ”N ' ‘ L.- .M/ "\O? -fi'h/CQ: l" . C. C?) 9 Q; 1 ' On (a, S: (3% \O " (I. Use curved :lI‘I‘OWS to Show Ilu: flow ul'clcclrnns in the following rcucliun: { IO pls} GD 9 H20 '5' H20 —"' H}() + OH Your signature {ill ink) . - Us 7‘, K I-prluin clearly why u curlmnaninn is expected 10 he pyrmnidul whcrcus :1 curimnculiun is expected to he lrigunul planar. I It) Ins] LUQ LLOIL \fS E P I? ( magma; S. few 0 [305610131 PtLi/L rUpL-L Off-JUN} 3 #1) fit? {JP Hf) {{f‘fl (“J 9/}5 +(I‘V'YW (,1 (1m LJ {—11.13 0’ {It}! Wm RE QLL [Jag S {(2fo 0.5 . F{.}:5£', w e, (Jajg-Q/La'h’} £442, H125 ”WM )1“) (It (“m/‘1‘ 3' U P flu 21.00113 (:1 lfitml-‘CL (1/V\ (rug-LON l—ZVL CL (2an may) 20y"; A)¢1.'3?QLII paw S‘ tfiQpI'CZEC’Y'IS) 7%,me Prams 4.0 bends: _<.' _ {3631.5} Lyme. [JG/TIC [Doug . 7172‘ WQMII‘ Enl‘ S‘Plpt‘mahcm (2)” 775212 e /"2 ohm S' 3 .2") o 421,20]me Logo”) 1%}? can/3m? L57 [)1 {Mi-“11PM % Iv 77% Cam/on QIL/ an [3) [1,0 5,3,1 [77 SJ)! 2 Paid-’3’) T CLO 7%)le [Swat/L53 {Dz—LL”) 5 .. H 2mg.) )‘1-WCiflL01’JLU)”l1 Sapma/A 2/11 i' u) D A ‘I—CLU‘H-E' 0/. La) Airy} ”f/CE 8/)“;{405' CLbC/UJ} +50. CAN/3:00 CUM; “[‘fuamoofl PPQMQQ 1 Your signallurc (in ink) _ _ 0 ...
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