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Exam 2 102 2009 Solution

# Exam 2 102 2009 Solution - MAE 102 MIDTERM EXAM 2 FALL 2009...

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Unformatted text preview: MAE 102 MIDTERM EXAM 2 FALL 2009 1. The disc of radius R = 1 :11 rolls without slipping. Point 0 has velocity 90 to the right. In the position shown, the magnitude of the velocity vector of point A is 4111/5, and the aoceleratim vector of point A is 8111/32 downward. Find the velocity and acceleration vectors of point B. 2. Twosmallballs, eachofmassm, areconnectedby amasslessrigidrodoflengthf. BallA slides without friction on the horizontal ﬂoor. The system is released from rest with 6 = 90°, and ball 3 falls to the right. Find the velocity of the center of mass and the angular velocity of the rod when 3 = 30°. Giveanswersintermsofm,ga.nd£. 3. Block A has mass 2m, and Block B has mass m. Initially, block A has velocity 1J0 to the right, block B is at rest against the spring, and the spring is undeﬂected. Block B is m attached to the spring. 011 impact, blocks A and B stick together. [a] What fraction of the initial energy is lost during the impact? (b) What fraction of the initial energy is lost after the impact? (c) Find the magnitude and direction of the ﬁnal velocity of the two blocks (after they leave the spring). 4. Two small balls, each ofmaas m, are connected by a. measleas rigid rod of length 2. Ball A slidw without friction on the horizontal ﬂoor, and a constant horizontal force F acts on ball A. Initially, the system is at rest. Q (b) If!) remains constant with 0058 = 3/5, the value ofF is i.mg ._ E 2 ‘5} Q— \$00599 0059- 9%”- M "Ma W uni} 6-30.5Q '31;- £.S)ﬁQF-£W56N: H6“;— 5 “W érO\$N=2~V7 F: “9566 [c ) If F— — 3mg, the angular acceleration of the rod fer the initial position is %§sin9—§o039 ' 1-+oos 9 my; 11% “mi?” om. WWW f“ 3cosﬂ— 2sin3 in %—2— 1+coa :9 F: frailty % “13%?” I cosﬂ—2ﬁjgﬂ 51+COS 9 ...
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Exam 2 102 2009 Solution - MAE 102 MIDTERM EXAM 2 FALL 2009...

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