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Unformatted text preview: the middle digit. Therefore 5 4 4 9 8 7 [_____/12] 2. Suppose A , B , C are all independent events with P A 0.3, P B 0.4, P C 0.5. [4] (a) Find P A B C The easiest way of doing this is to use part (c) and take 1 − the answer to part (c). Otherwise use the fact that A , B , C are all independent and then P A B C P A P B P C − P AB − P BC − P AC P ABC 0.7 0.4 0.5 − 0.7 0.4 − 0.4 0.5 − 0.7 0.5 0.7 0.4 0.5 [4] (b) Find P A B By independence of B , A this is P A B P A P B 0.3 0.6 0.18 [4] (c) Find the probability that none of the events A , B or C occur. This is P A B C P A P B P C 0.3 0.6 0.5 Alternative: use 1 − answer to part (a)....
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 Fall '06
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 Probability theory, Numerical digit, three digits, middle digit, 70. 40. 5

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