ch16_eng

# ch16_eng - SOLUTION MANUAL ENGLISH UNIT PROBLEMS CHAPTER 16...

This preview shows pages 1–8. Sign up to view the full content.

SOLUTION MANUAL ENGLISH UNIT PROBLEMS CHAPTER 16 FUNDAMENTALS of Thermodynamics Sixth Edition SONNTAG BORGNAKKE VAN WYLEN

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Sonntag, Borgnakke and van Wylen CHAPTER 16 CONTENT CHAPTER 16 SUBSECTION PROB NO. Correspondence table Stagnation properties 74-76 Momentum Equation and Forces 77-78 Velocity of Sound 79 Reversible Flow Through a Nozzle 80-82, 84 Normal Shocks 83 Nozzles, Diffusers and Orifices 85-87 New 5th SI New 5th SI 74 44E - 81 52E 43 75 45E 24 82 51E 41 76 46E 25 83 53E 55 77 47E 29 84 55E 53, 54 78 48E 34 85 54E 62 79 49E 37 86 56E 63 80 50E 47 87 57E 71
Sonntag, Borgnakke and van Wylen Stagnation properties 16.74 E Steam leaves a nozzle with a velocity of 800 ft/s. The stagnation pressure is 100 lbf/in 2 , and the stagnation temperature is 500 F. What is the static pressure and temperature? h 1 = h o1 - V 1 2 /2g c = 1279.1 - 800 2 2 × 32.174 × 778 = 1266.3 Btu lbm s 1 = s 0 = 1.7085 Btu/lbm R (h, s) Computer table P 1 = 88 lbf/in. 2 , T = 466 F

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Sonntag, Borgnakke and van Wylen 16.75 E Air leaves the compressor of a jet engine at a temperature of 300 F, a pressure of 45 lbf/in 2 , and a velocity of 400 ft/s. Determine the isentropic stagnation temperature and pressure. h o1 - h 1 = V 1 2 /2g c = 400 2 /2 × 32.174 × 778 = 3.2 Btu/lbm T o1 - T - 1 = (h o1 - h 1 )/C p = 3.2/0.24 = 13.3 T o1 = T + T = 300 + 13.3 = 313.3 F = 773 R P o1 = P 1 () T o1 /T 1 k k-1 = 45(773/759.67) 3.5 = 47.82 lbf/in 2
Sonntag, Borgnakke and van Wylen 16.76 E A meteorite melts and burn up at temperatures of 5400 R. If it hits air at 0.75 lbf/in. 2 , 90 R how high a velocity should it have to reach such temperature? Assume we have a stagnation T = 5400 R h 1 + V 1 2 /2 = h stagn. Extrapolating from table F.5, h stagn. = 1515.6, h 1 = 21.4 Btu/lbm V 1 2 /2 = 1515.6 – 21.4 = 1494.2 Btu/lbm V 1 = 2 × 32.174 × 778 × 1494.2 = 8649 ft/s

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Sonntag, Borgnakke and van Wylen Momentum Equation and Forces 16.77 E A jet engine receives a flow of 500 ft/s air at 10 lbf/in. 2 , 40 F inlet area of 7 ft 2 with an exit at 1500 ft/s, 10 lbf/in. 2 , 1100 R. Find the mass flow rate and thrust. m . = ρ A V ; ideal gas ρ = P/RT m . = (P/RT)A V = 10 × 144 53.34 × 499.7 × 7 × 500 = 189.1 lbm/s F net = m . ( V ex - V in ) = 189.1 × (1500 - 500) / 32.174 = 5877 lbf Inlet High P Low P exit cb F net The shaft must have axial load bearings to transmit thrust to aircraft.
Sonntag, Borgnakke and van Wylen 16.78 E A water turbine using nozzles is located at the bottom of Hoover Dam 575 ft below the surface of Lake Mead. The water enters the nozzles at a stagnation

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 10/17/2010 for the course ME 335 taught by Professor Chaturvedi during the Spring '10 term at Old Dominion.

### Page1 / 16

ch16_eng - SOLUTION MANUAL ENGLISH UNIT PROBLEMS CHAPTER 16...

This preview shows document pages 1 - 8. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online