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Unformatted text preview: Anderson, Matthew Homework 6 Due: Oct 17 2007, 11:00 pm Inst: Opyrchal, H 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points An outfielder throws a 1 . 1 kg baseball at a speed of 43 m / s and an initial angle of 10 . 3 . What is the kinetic energy of the ball at the highest point of its motion? Correct answer: 984 . 438 J. Explanation: Given : m = 1 . 1 kg , = 10 . 3 , and v = 43 m / s . At its highest point, the baseball has only a horizontal velocity v x = v cos contributing to its kinetic energy, so the kinetic energy is K = 1 2 mv 2 x = 1 2 m ( v cos ) 2 = 1 2 (1 . 1 kg)[(43 m / s) cos10 . 3 ] 2 = 984 . 438 J . keywords: 002 (part 1 of 2) 10 points A force ~ F = F x + F y acts on a particle that undergoes a displacement of ~s = s x + s y . Let: F x = 5 N, F y =- 5 N, s x = 3 m, and s y = 1 m. Find the work done by the force on the particle. Correct answer: 10 J. Explanation: The work is given by W = ~ F ~s = F x s x + F y s y = (5 N)(3 m) + (- 5 N)(1 m) = 10 J . 003 (part 2 of 2) 10 points Find the angle between ~ F and ~s . Correct answer: 63 . 435 . Explanation: Since W = ~ F ~s = fl fl fl ~ F fl fl fl | ~s | cos . The first and the third sides can be solved for to give = cos- 1 W fl fl fl ~ F fl fl fl | ~s | ....
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