Exam #2 Review (Kinetic) Clicker Questions Answers

# Exam #2 Review (Kinetic) Clicker Questions Answers -...

This preview shows pages 1–4. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Consider this reaction What is the rate law for this reaction? 1 . r a t e = k [ N O 2 ] [ C O ] 2 . r a t e = k [ N O ] [ C O 2 ] 3 . r a t e = k [ N O 2 ] 2 4 . r a t e l a w c a n n o t b e . . . 33% 59% 0% 8% Remember: the rate law cannot be determined without measured data. In particular, it cannot be determined from the reaction stoichiometry. NO 2 ( g ) + CO ( g ) → NO ( g ) + CO 2 ( g ) 1. rate = k [NO 2 ][CO] 2. rate = k [NO][CO 2 ] 3. rate = k [NO 2 ] 2 4. rate law cannot be determined from info. given Clicker Questions: [1. Press “ Go ”; 2. Press “ 43 ”; 3. Press “ Go ”] For the reaction: 2A + B → BA 2 Doubling [A] doubles the rate of the reaction. However, tripling [B] increases the rate 9 × . What is the correct rate law expression? 1 . r a t e = k [ A ] [ B ] 2 . r a t e = k [ A ] 2 [ B ] 3 . r a t e = k [ A ] [ B ] 2 4 . r a t e = k [ A ] [ B ] 3 1% 15% 77% 7% The rate order on A is one, because a doubling of [A] leads to a doubling of reaction rate. However, the rate order on B is two, because a tripling of [B] leads to a 9 × = (3) 2 increase in reaction rate. 1. rate = k [A][B] 2. rate = k [A] 2 [B] 3. rate = k [A][B] 2 4. rate = k [A][B] 3 It is observed that the rate of the first order reaction, CH 3 NC( g ) → CH 3 CN( g ) (rate law: rate = k[CH...
View Full Document

{[ snackBarMessage ]}

### Page1 / 13

Exam #2 Review (Kinetic) Clicker Questions Answers -...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online