Isaac Probability Quiz 1.25.10

Isaac Probability Quiz 1.25.10 - Isaac Moreno PROBABILITY...

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Isaac Moreno PROBABILITY QUIZ 1-25-2010 1. a) c+f = c(.55) + f(.45) = 1.00 b) P of a+b+d+e = .25+.30+.10+.35 = 1.00 c) P (A on exam) = .25/.55 = .45 = 45% conditional probability d) P (A on course) = .25+.10+.30 = .65 = 65% probability e) P (B/A) = P (B) = .35 or P (A/B) = P (A) = .22 P (B/A) .25/.55 = .45 P (B) does not equal to P (B/A) Sum of P (g) = .35 P (A/C) P (A/C) = .45 .35 does not equal to .45 [making it dependent] 2. a) [ 250 subjects ] under weight normal weight overweight total < 3 days .024 .06 .012 .096 3-7 days .12 .38 .08 .58 > 7 .056 .16 .108 .324 total .2 .6 .2 1.00 b) P (R< 3 days) = .096 = 9.6% of recovery in < 3 days c) Given >7 = .324, P (OW) = .108 .108/.324 = .33 = 33% overweight 3. Manufacturer A1 = .90 over 40 hrs Manufacturer A2 = .75 over 40 hrs .10 under 40 hrs .25 under 40 hrs P (A1) = .60 P (G|A1) = .90 P (B|A1) = .10 P (A2) = .40 P (G|A2) = .75 P (B|A2) = .25 Using Bayes’ theorem: P (A1) x P (G|A1) = .60 x .90 = .54 P (A1) x P (B|A1) = .60 x .10 = .06
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This note was uploaded on 10/21/2010 for the course MATH Stat2001 taught by Professor Helmsley during the Spring '10 term at Chapman University .

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Isaac Probability Quiz 1.25.10 - Isaac Moreno PROBABILITY...

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