SolutionsSet02

SolutionsSet02 - Homework Solutions Set 02 Problem 1...

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Homework Solutions Physics 121 Set 02 Spring 2008 - 1 - Problem 1 In order to study the motion of the black, we divide the 16-second period into 6 smaller periods, during which the force is constant. The relevant information is summarized in the following table. t start (s) t stop (s) F (N) a (m/s 2 ) v start (m/s) V stop (m/s) x start (m) x stop (m) 0 2 2 0.5 0 1 0 1 2 6 8 2 1 9 1 21 6 8 4 1 9 11 21 41 8 12 0 11 11 41 85 12 14 8 2 11 15 85 111 14 16 6 1.5 15 18 111 144 The following relations were used to related to final velocity and position in each period to the initial velocity and position in that period: v stop = v start + a t stop ! t start ( ) x stop = x start + v start t stop ! t start ( ) + 1 2 a t stop ! t start ( ) 2
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Homework Solutions Physics 121 Set 02 Spring 2008 - 2 - The average velocity during the 16-second time period is equal to the ratio of the change in position and the change in time: 144/16 = 9 m/s. The average acceleration during this period is equal to the ratio of the change in velocity and the change in time: 18/16 = 1.125 m/s 2 . Using the same technique, we can also calculate the distance the block traveled in the first 10.9 s. We find that the distance is 72.9 m.
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Homework Solutions Physics 121 Set 02 Spring 2008 - 3 - Problem 2 The rocket in this problem is exposed to two forces: The gravitational force
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SolutionsSet02 - Homework Solutions Set 02 Problem 1...

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