Unformatted text preview: Ans:; Okk, I know the formula is, lamda=h/mu Where m is mass, u is velocity , h= 6.63* 10^-34 Then I can find the wavelength. .but it says about thermal neutrons?? So at room temperature the situation will be different. .What should I do?? And it should b a beam of neutron. .while we have the mass of one neutron. I am confused. 6. How many Photons at 586 nm must be absorbed to melt 5.50*10^2 of ice? It takes 334 J to melt 1 g of ice? On average how many water molecules does one photon convert from ice to water? Ans:: I did the first one. But now sure about that. Its also, lamda=hc/E I guess. .not sure. .I just used the unit of h to get the number of photons. But not sure about it....
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- Fall '10
- Light, 1 W, 1 g, 1 j, thermal neutrons