CHEM 2B Titration+Flowchart

CHEM 2B Titration+Flowchart - 3 O + ] pOH = -log[OH-] pH +...

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Enderle – Spring 2006 Solving Titration Problems Identify the type: SASB, SBSA, WASB, or WBSA Find mmol of A & B. Which one is in excess? SA or SB ( SA or SB region ) Solve using any combo: pH = -log [H
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Unformatted text preview: 3 O + ] pOH = -log[OH-] pH + pOH = 14.00 WA or WB ( buffer region ) Solve using H-H mmol A = mmol B (equivalence point ) SASB or SBSA: pH = 7 WASB or WBSA: Use ICE No titrant added...
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This note was uploaded on 10/22/2010 for the course CHE CHE 2B taught by Professor Toupadakis during the Fall '09 term at UC Davis.

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