C8-activities - ACTIVITY 8-1 Use mA k and V vs 5 k v1 vs 10 k 6i x v2 ACTIVITY 8-1 vs 5 k v1 vs 10 k 6i x v2 ix 2 k 0 1 k ix 2 k 0 1 k 4 Nodes 1

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1 ACTIVITY 8-1 s v 5 k Ω 10 k Ω 2 k Ω 1 k Ω x i x 6i 4 Nodes 1 Voltage Source 1 (Ref) 2 Unknown Node Voltages 0 s v 1 v 2 v Use mA, k , and V Ω ACTIVITY 8-1 s v 5 k Ω 10 k Ω 2 k Ω 1 k Ω x i x 6i Step 1: Find Constraint Equation 0 s v 1 v 2 v x1 2 Need to Relate i to v , v ACTIVITY 8-1 s v 5 k Ω 10 k Ω 2 k Ω 1 k Ω x i x 6i s1 x vv Ohm's Law: i 5 = 0 s v 1 v 2 v xs1 6i 1.2v 1.2v =− ACTIVITY 8-1 s v 5 k Ω 10 k Ω 2 k Ω 1 k Ω x i x 6i 0 s v 1 v 2 v 1 1s 12 1 x KCL at Node v : vv vv v 6i 0 51 0 2 + ++ = ACTIVITY 8-1 s v 5 k Ω 10 k Ω 2 k Ω 1 k Ω x i x 6i 0 s v 1 v 2 v 2 22 1 x KCL at Node v : vvv 6i 0 11 0 +− = ACTIVITY 8-1 21 2 x Node v : v ( ) v (1 ) 6i 10 10 −+ += s 2 x v 111 1 Node v : v ( ) v ( ) 6i 02 1 0 5 +++− =− [ ] G Matrix is Still Symmetric x But Right Hand Side Contains i
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2 ACTIVITY 8-1 xs1 Use Constraint Equation :6i 1.2v 1.2v =− No Longer a Symmetric Matrix s 11 2 s 1 12 s v Node v : v (.8) v ( .1) 1.2v 1.2v 5 .4v .1v v +−=− + => − = − 21 2 s 1 12 s Node v : v ( .1) v (1.1) 1.2v 1.2v 1.1v 1.1v 1.2v −+ = => + = ACTIVITY 8-1 s 1 2s v v .4 .1 1.1 1.1 v 1.2v −−
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This note was uploaded on 10/21/2010 for the course ECSE 2010 taught by Professor Millard during the Spring '08 term at Rensselaer Polytechnic Institute.

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C8-activities - ACTIVITY 8-1 Use mA k and V vs 5 k v1 vs 10 k 6i x v2 ACTIVITY 8-1 vs 5 k v1 vs 10 k 6i x v2 ix 2 k 0 1 k ix 2 k 0 1 k 4 Nodes 1

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