C15-activities - ACTIVITY 15-1 Upper Position for t < 0...

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1 ACTIVITY 15-1 32 V 4 Ω 12 Ω 12 Ω 3 Ω 1.8 H i v + Upper Position for t 0 < Lower Position at t 0 = Upper Position at t 0.3 s = Find i(t) and v(t) ACTIVITY 15-1 Two Switching Times Switches Down at t 0 = Need to Solve the Differential Equations for i(t) and v(t) During Two Time Intervals: 0 t .3 seconds .3 t ≤ ≤∞ Switches Back Up at t .3 seconds = ACTIVITY 15-1 Follow the 4 Step Procedure During Each Interval: For 0 t .3 s: ≤≤ 01 SS1 01 SS1 1 01 Find i , i , v , v , where t 0 s τ = ( ) () 1 1 t SS1 01 SS1 t SS1 01 SS1 i(t) i i i e v(t) v v v e =+− ACTIVITY 15-1 For .3 t : 02 SS2 02 SS2 2 02 Find i , i , v , v , ; where t 0.3 , s = ( ) 2 2 (t-.3) SS2 02 SS2 (t-.3) SS2 02 SS2 i ( t ) i iie v v v e Follow the 4 Step Procedure During Each Interval: 01 Step 1: Draw Circuit at t t 0 −− == 01 Step 2: Draw Circuit at t 0 : ++ = Step 3: Draw Circuit at t →∞ Step 4: Draw Dead Network - eq1 1 Find R , 01 01 Find i , v L Find i (0 ), i(0 ) and v(0 ) SS1 SS1 Find i , v 4 Step Process: ACTIVITY 15-1 32 V 4 Ω 12 Ω 12 Ω 3 Ω v(0 ) + DC Steady State L is a Short Ckt Up Position L F ind
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C15-activities - ACTIVITY 15-1 Upper Position for t &lt; 0...

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