C24-act - − ACTIVITY 24-1 3 o F D E 55 25 j60 65 /112.6...

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1 ELECTRIC CIRCUITS ECSE-2010 Class 24 ACTIVITY 24-1 Aj 5 = − B4 j 2 =−+ C1j 3 =+ Find D A x B = * D Find E C = ACTIVITY 24-1 Aj 5 =− B4 j 2 =− + C1j 3 =+ Find D A x B = () j5 x ( 4 j2) =− − + 2 j20 j 10 =− 2 j1 =− D1 0j 2 0 =+ ACTIVITY 24-1 * D Find E C = D1 0j 2 0 =+ C1j 3 = + * C1 j 3 => = − 10 j20 E 1j 3 + = 1j 3 x 1j 3 + + 10 j30 j20 60 19 ++− = + 50 j50 5j 5 10 −+ == + ACTIVITY 24-1 0 j120 A4 e = B2 6j 1 5 =− 0 C 2/ 150 =− 0 D2 / 3 0 = * A x B Find E C = ACTIVITY 24-1 0o E 60 (angle of 240 ) 60/240 == * o0 A 4/ 120 , A 4/ 120 =− = > =+ Convert All to Polar Form * 00 0 A B 4/120 30/ 30 E C2 / 1 5 0 == o B 26

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2 ACTIVITY 24-1 o E6 0 / 2 4 0 = 60 Real Imag 0 30 30 52 E3 0 j
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Unformatted text preview: − ACTIVITY 24-1 3 o F D E 55 25 j60 65 /112.6 => = − − = − + = 3 F D E 55 = − − Convert All to Rectangular Form 3 0 3 D (2/30 ) 8/90 j8 = = = E 60/240 30 j52 = = − − 55 55 j0 = + ACTIVITY 24-1 Real Imag 25 − j60 o F 25 j60 65 /112.6 = − + = F 67.4 65 180 67.4 112.6 − = Activity 24-2 ± Using Impedance to develop the s-Domain Circuit representation Activity 24-2...
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This note was uploaded on 10/21/2010 for the course ECSE 2010 taught by Professor Millard during the Spring '08 term at Rensselaer Polytechnic Institute.

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C24-act - − ACTIVITY 24-1 3 o F D E 55 25 j60 65 /112.6...

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