C25-act - ELECTRIC CIRCUITS ECSE-2010 Class 25 ACTIVITY...

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1 ELECTRIC CIRCUITS ECSE-2010 Class 25 ACTIVITY 25-1 1 v + 2 v + s v Note Symbol for AC Input 1 2 s 0 2 v 4 cos(1000t) V v 3 cos(1000t 90 ) V = =+ 1 1 Find V and v (t) Construct Phasor Diagram Time Domain ACTIVITY 25-1 1 V +− 2 V + s V 1 2 0 s 0 2 V4 / 0 V V3 / 9 0 V = = 12 s KVL: V V V += Frequency Domain 4j 0 V 0j 3 V 1000 ω = ACTIVITY 25-1 1 + 2 V + s V 1 2 Frequency Domain s 2 j 0 V V0 j 3 V = + 1s2 VVV4 j 3 V =−= 0 5/ 36.9 V =− 1000 = ACTIVITY 25-1 1 2 v + s v 1 2 Time Domain 0 1 V 1000 = 0 1 v (t) 5cos(1000t 36.9 ) V ACTIVITY 25-1 s V 2 V 2 V 0 1s 2 V V ( V ) 4 j3 − = −=− VVV 4 j3 Real Imaginary Phasor Diagram 5 0 36.9 j3
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2 ACTIVITY 25-2 v(t) 120 cos(5000t) V = v(t) 20 Ω 5 Ω 20 F μ 4 mH i C v + C i L i Time Domain CC L Find i(t), i (t), v (t), and i (t) in AC Steady State ACTIVITY 25-2 V 20 Ω 5 Ω C 5 j Zj 1 0 (5000)(2x10 ) = −= Ω j20 Ω I C V + C I L I Frequency Domain 0 V 120/ 0 V = 5000 ω = j10 −Ω 3 L Z j(5000)(4x10 ) j20 == Ω ACTIVITY 25-2 0 20 Ω 5 Ω j10 j20 Ω I C V + C I L I 5 is in Series with j20 ΩΩ eq1 Z5 j 2 0 =+ Ω 5000 = ACTIVITY 25-2 eq1 Z is in parallel with j10 0 20 Ω j10 Ω
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This note was uploaded on 10/21/2010 for the course ECSE 2010 taught by Professor Millard during the Spring '08 term at Rensselaer Polytechnic Institute.

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C25-act - ELECTRIC CIRCUITS ECSE-2010 Class 25 ACTIVITY...

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