01-10-10 - Friday, October-01-10 Circular motion kinematics...

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Friday, October-01-10 - Circular motion kinematics - Particle Dynamics: nothing new o There is no “Centrifugal force” o A has a radial component as well as a tangential component o Example: pendulum Calculate the tension in string when the pendulum is as the lowest point in the swing Given: mass m, length L , and speed at the lowest point Forces acting upon it are the force of tension and the force of m*G If the tension is greater then the wait we will have a net upward force equal to the FT-MG(which is equal to ma) o Then the acceleration would be in an upward direction Because its moving in a circle we can get that acceleration in different means o The acceleration is also equivalent to V o 2 / L o Tension has to be greater if the pendulum is in movement o There might be a tangential acceleration to this as well o But there isn’t at this case because there are no horizontal forces affecting it and the tangential acceleration would have to be horizontal Water in bucket which is put in a circular motion and due to centripetal force
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This note was uploaded on 10/22/2010 for the course PHYSICS 1D03 taught by Professor N. mckay during the Spring '08 term at McMaster University.

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01-10-10 - Friday, October-01-10 Circular motion kinematics...

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