solutions 3 - Patel, Kinal Homework 3 Due: Sep 11 2007,...

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Unformatted text preview: Patel, Kinal Homework 3 Due: Sep 11 2007, 7:00 pm Inst: D Weathers 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points Two sides of a triangle are 11 . 9 cm and 32 . 5 cm, with the included angle 109 . a) What is the length of the third side? Correct answer: 38 . 0748 cm. Explanation: Basic Concepts: The Law of Cosines states c 2 = a 2 + b 2- 2 ab cos C The Law of Sines states sin A a = sin C c Solution a c b A C We are looking for the side opposite the given angle so c = p a 2 + b 2- 2 ab cos C 002 (part 2 of 2) 10 points b) What is angle opposite the side 11 . 9 cm? Correct answer: 17 . 1884 . Explanation: sin A a = sin C c A = arcsin a sin C c keywords: 003 (part 1 of 1) 10 points A high fountain of water is located at the center of a circular pool as in the figure. A student walks around the pool and estimates its circumference to be 214 m. Next, the student stands at the edge of the pool and uses a protractor to gauge the angle of elevation of the top of the fountain to be 55 . 8 . How high is the fountain?...
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This note was uploaded on 10/22/2010 for the course PHYS PHYS 1710 taught by Professor Weathers during the Fall '07 term at North Texas.

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solutions 3 - Patel, Kinal Homework 3 Due: Sep 11 2007,...

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