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Unformatted text preview: Patel, Kinal Homework 22 Due: Nov 30 2007, 7:00 pm Inst: D Weathers 1 This printout should have 11 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points A car tire gauge is used to fill a tire to a gauge pressure of 42 . 5 lb / in 2 on a cold morning when the temperature is 9 C. Atmospheric pressure is 14 . 7 lb / in 2 and 0 C = 273 K. What would the tire gauge read when the tire has been heated up to 30 . 5 C? Correct answer: 51 . 0583 lb / in 2 . Explanation: Given : P atm = 1 atm = 14 . 7 lb / in 2 , P 1 g = 42 . 5 lb / in 2 , T 1 = 9 C = 264 K , and T 2 = 30 . 5 C = 303 . 5 K . Since the rubber is not expanding, the volume stays fixed. From the ideal gas law P V = n R T and P 1 = P 1 g + P atm = 42 . 5 lb / in 2 + 14 . 7 lb / in 2 = 57 . 2 lb / in 2 , so P 1 V T 1 = P 2 V T 2 P 2 = P 1 T 2 T 1 P 2 g + P atm = P 1 T 2 T 1 P 2 g = P 1 T 2 T 1 P atm = (57 . 2 lb / in 2 )(303 . 5 K) 264 K 14 . 7 lb / in 2 = 51 . 0583 lb / in 2 . keywords: 002 (part 1 of 1) 10 points At 24 m below the surface of the sea (den sity of 1223 kg / m 3 ), where the temperature is 4 C, a diver exhales an air bubble having a volume of 0 . 4 cm 3 . The acceleration of gravity is 9 . 8 m / s 2 and the atmospheric pressure is 102000 Pa. If the surface temperature of the sea is 18 C, what is the volume of the bubble immediately before it breaks the surface? Correct answer: 1 . 60527 cm 3 . Explanation: Given : L = 24 m , = 1223 kg / m 3 , T 1 = 4 C = 277 K , V 1 = 0 . 4 cm 3 , and T 2 = 18 C = 291 K ....
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This note was uploaded on 10/24/2010 for the course PHYS PHYS 1710 taught by Professor Weathers during the Spring '07 term at North Texas.
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