solutions 24

# solutions 24 - Patel Kinal Homework 24 Due Dec 7 2007 7:00...

This preview shows pages 1–2. Sign up to view the full content.

Patel, Kinal – Homework 24 – Due: Dec 7 2007, 7:00 pm – Inst: D Weathers 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. 001 (part 1 oF 1) 10 points The molar mass oF O 2 is 32 g / mol, and the molar mass oF He is 4 g / mol. The rms speed oF a helium atom at room temperature is 1602 m / s. What is the rms speed oF an oxygen (O 2 ) molecule at this temperature? Correct answer: 566 . 393 m / s. Explanation: Let : v He = 1602 m / s , m He = 4 g / mol and m O 2 = 32 g / mol . According to the molecular model oF ideal gas, v He = s 3 k B T m He v O 2 = s 3 k B T m O 2 v O 2 v He = r m He m O 2 v O 2 = v He r m He m O 2 = (1602 m / s) s 4 g / mol 32 g / mol = 566 . 393 m / s . keywords: 002 (part 1 oF 1) 10 points The universal gas constant is 8 . 31451 J / K · mol. Calculate the change in internal energy oF 8 mol oF helium gas when its temperature is increased by 5 . 1 K. Correct answer: 508 . 848 J. Explanation: Given : n = 8 , R = 8 . 31451 J / K · mol and Δ T = 5 . 1 K . The internal energy oF the monoatomic ideal gas is U = 3 2 n R T So, Δ U = 3 2 n R Δ T = 3 2 (8)(8 . 31451 J / K · mol)(5 . 1 K) = 508 . 848 J .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 3

solutions 24 - Patel Kinal Homework 24 Due Dec 7 2007 7:00...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online