solutions 24 - Patel, Kinal Homework 24 Due: Dec 7 2007,...

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Patel, Kinal – Homework 24 – Due: Dec 7 2007, 7:00 pm – Inst: D Weathers 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. 001 (part 1 oF 1) 10 points The molar mass oF O 2 is 32 g / mol, and the molar mass oF He is 4 g / mol. The rms speed oF a helium atom at room temperature is 1602 m / s. What is the rms speed oF an oxygen (O 2 ) molecule at this temperature? Correct answer: 566 . 393 m / s. Explanation: Let : v He = 1602 m / s , m He = 4 g / mol and m O 2 = 32 g / mol . According to the molecular model oF ideal gas, v He = s 3 k B T m He v O 2 = s 3 k B T m O 2 v O 2 v He = r m He m O 2 v O 2 = v He r m He m O 2 = (1602 m / s) s 4 g / mol 32 g / mol = 566 . 393 m / s . keywords: 002 (part 1 oF 1) 10 points The universal gas constant is 8 . 31451 J / K · mol. Calculate the change in internal energy oF 8 mol oF helium gas when its temperature is increased by 5 . 1 K. Correct answer: 508 . 848 J. Explanation: Given : n = 8 , R = 8 . 31451 J / K · mol and Δ T = 5 . 1 K . The internal energy oF the monoatomic ideal gas is U = 3 2 n R T So, Δ U = 3 2 n R Δ T = 3 2 (8)(8 . 31451 J / K · mol)(5 . 1 K) = 508 . 848 J .
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solutions 24 - Patel, Kinal Homework 24 Due: Dec 7 2007,...

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