solutions 11

# solutions 11 - Patel, Kinal Homework 11 Due: Feb 29 2008,...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Patel, Kinal Homework 11 Due: Feb 29 2008, 7:00 pm Inst: Weathers 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points A positively charged particle moving paral- lel to the y-axis enters a magnetic field (point- ing toward the bottom of the page), as shown in the figure below. y z v x ~ B ~ B + q Figure: is in the x-direction, is in the y-direction, and k is in the z-direction. What is the initial direction of deflection? 1. b F = + k 2. b F =- k 3. b F = + correct 4. b F = + 5. b F =- 6. b F =- 7. ~ F = 0 ; no deflection Explanation: Basic Concepts: Magnetic Force on a Charged Particle: ~ F = q~v ~ B Right-hand rule for cross-products. b F ~ F k ~ F k ; i.e. , a unit vector in the F direc- tion. Solution: The force is ~ F = q~v ~ B . ~ B = B - k , ~v = v (- ) , and q > , therefore , ~ F = + | q | ~v ~ B = + | q | v B h (- ) - k i = + | q | v B (+ ) b F = + . This is the fifth of eight versions of the problem. keywords: 002 (part 1 of 1) 10 points A proton moving at 5 . 9 10 6 m / s through a magnetic field of 3 . 1 T experiences a magnetic force of magnitude 2 10- 12 N. The charge of proton is 1 . 60218 10- 19 C and the mass of proton is 1 . 67262 10- 27 kg. What is the angle between the protons velocity and the field? Correct answer: 43 . 0397 . Explanation: Let : E = 2 10- 12 N , B = 3 . 1 T , v = 5 . 9 10 6 m / s , q p = 1 . 60218 10- 19 C , and m p = 1 . 67262 10- 27 kg . The Lorentz force acting on a moving charged particle in a magnetic field is F = q v B sin , where q is the charge, v is the speed, B is the magnetic field. So thus the angle between the velocity and the field is = arcsin F q v B = arcsin (2 10- 12 N) (1 . 60218 10- 19 C) 1 (5 . 9 10 6 m / s) (3 . 1 T) = 43 . 0397 . Patel, Kinal Homework 11 Due: Feb 29 2008, 7:00 pm Inst: Weathers 2 keywords: 003 (part 1 of 3) 10 points The magnetic field over a certain range is given by ~...
View Full Document

## This note was uploaded on 10/24/2010 for the course PHYS PHYS 2220 taught by Professor Weathers during the Spring '08 term at North Texas.

### Page1 / 5

solutions 11 - Patel, Kinal Homework 11 Due: Feb 29 2008,...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online