PracticeEx3_Soln

# PracticeEx3_Soln - Solutions for the Practice Exam 3...

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Solutions for the Practice Exam 3 Problem 1. (a) Chemical potentials are idential to make the total Gibbs free energy minimum. : True (b) 2 ( NO 2 (g)) = (N 2 O 4 (g)): False (c) Liquid droplets form spheres to minimize the surface energy. : False (d) False (e) Mixing is spontaneous. : True Problem 2. The Clapeyron equation for solid-liquid boundary is *) ( * *) ( T T V T H P P melt melt melt melt H V T P P T T * *) ( *) ( Note that V melt is the volume change of one mole and one mole of water is 18 g. So V melt = V(l) – V(s) = ) / ( 10 9 . 0 18 ) / ( 10 1 18 ) ( ) ( 3 6 3 6 m g g m g g s M l M = -2 10 -6 m 3 When P * = 1 atm = 101000 Pa, T* = 273.15K. When P = 30000 Pa, the melting temperature T will be K H V T P P T T melt melt 156 . 273 6000 ) 10 2 ( 15 . 273 ) 101000 30000 ( 15 . 273 * *) ( * 6 The melting temperature of ice virtually does not change. Problem 3.

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## This note was uploaded on 10/24/2010 for the course CH 153K taught by Professor Wilson during the Fall '10 term at University of Texas.

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PracticeEx3_Soln - Solutions for the Practice Exam 3...

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