Math 157-WK 4

# Math 157-WK 4 - Math 157 Week 4 Chapter 10 Page 584 Prob 2...

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Math 157 – Week 4 Chapter 10 Page # Prob. Solution 584 2 a.) b.) c.) QP and VU d.) e.) Plane RTSU and Plane PQXRS f.) g.) P.Q.,R h.) QXR; VYU 585 10 12 14 DKLJ trapezoid; DFMK rectangle; DELK square 20 True, Since any line is contained in an infinite number of planes and since collinear points are on same line, collinear points are coplanar. 26 True; because to be classified as a right triangle one angle must be a 90 angle, the angle of an obtuse extends past 90 32 No; if the line is part of a cube the three points can be contained in more than one plane. 599 2 The centroid is the point at which the medians of a triangle intersect. It is the center of gravity of a triangular model 8 If the median is equal to 36 units than the centroid units, and 12 units from the midpoint of the side of the triangle opposite the vertex. 12 Since there are two vertices of degree 3, an odd degree, the trails can be traversed by starting at one vertex of odd degree and finishing at the other vertex of odd degree. 601 34 No, it is not a transversable. You cannot start on any vertex and only cross each bridge one time returning to the vertex you started on.

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613 2 2. a. 52 ° , vertical angles are congruent. b, c. 128 ° , supplementary angles sum to 180. d. 52 ° , alternate interiors. e. 128 ° , corresponding with respect to angle 2. f. 52 ° , corresponding with respect to the given 52 ° . g. 128 ° , corresponding with respect to angle 4. 4 4. 4 x + 10 = 6 x + 4, 2 x = 6, x = 3. So m 1 and 7 = 4(3) + 10 = 22 º. For parallel lines cut by a transversal, alternate exterior angles are congruent. . 6
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## This note was uploaded on 10/24/2010 for the course MAT 157 MAT 157 taught by Professor Kitchens during the Spring '10 term at University of Phoenix.

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Math 157-WK 4 - Math 157 Week 4 Chapter 10 Page 584 Prob 2...

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