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Math 157 – Week 4 Chapter 10
Page
#
Prob.
Solution
584
2
a.)
b.)
c.)
QP and VU
d.)
e.) Plane RTSU and Plane PQXRS
f.)
g.) P.Q.,R
h.) QXR; VYU
585
10
12
14
DKLJ trapezoid; DFMK rectangle; DELK square
20
True, Since any line is contained in an infinite number of planes and since
collinear points are on same line, collinear points are coplanar.
26
True; because to be classified as a right triangle one angle must be
a 90
angle, the angle of an obtuse extends past 90
32
No; if the line is part of a cube the three points can be contained in more than
one plane.
599
2
The centroid is the point at which the medians of a triangle intersect. It is the
center of gravity of a triangular model
8
If the median is equal to 36 units than the centroid
units, and 12
units from the midpoint of the side of the triangle opposite the vertex.
12
Since there are two vertices of degree 3, an odd degree, the trails can be
traversed by starting at one vertex of odd degree and finishing at the other
vertex of odd degree.
601
34
No, it is not a transversable. You cannot start on any vertex and only cross
each bridge one time returning to the vertex you started on.
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2
2. a. 52
°
, vertical angles are congruent. b, c. 128
°
, supplementary angles sum to 180.
d. 52
°
, alternate interiors.
e. 128
°
, corresponding with respect to angle 2. f. 52
°
,
corresponding with respect to the given 52
°
. g. 128
°
, corresponding with respect to
angle 4.
4
4. 4
x
+
10
=
6
x
+
4, 2
x
=
6,
x
=
3. So
m
1 and 7
=
4(3)
+
10
=
22 º. For parallel
lines cut by a transversal, alternate exterior angles are congruent.
.
6
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