# EXAM011 - EGM 2511 Exam 1 Fall 200’ NAME(Last First g ‘...

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Unformatted text preview: EGM 2511 Exam 1 Fall 200’ NAME (Last, First} g ‘ Section: 1592 or 1593 or 1594 (circle one) so no: 0 SHOW YOUR WORK - BOX OR UNDERLINE ANSWERS — Fan REQUIRED FOR EQUILIBRIUM PROBLEMS ‘5 V Problem 1. (30 pts) A force F of magnitude 250 N acts at the origin of a coordinate system. Knowing that Fx= 80 N, 6,. = 73.4”, and Fz> 0, determine (a) the components F J, and F2, (b) the angles 9x and 92. you a) Pg = £05 73.¢°[z5a).—: 7mm a; 75; ,4 Z .... \$02.;— 7/:¢22!1+Fé.1= 2-50 9 I"; :225837 EGM 2511 Exam 1 Fall 200' NANIE (Last, First) Section: 1592 or 1593 or 1594 (circle one) SHOW YOUR WORK - BOX 0R UNDERLINE ANSWERS — FBDs REQUIRED FOR EQUILIBRIUM PROBLEMS 3 2/ Problem 2. (30'pts) A 500 kN force is applied to the box below at A along the line from A to B. Find the component of the moment caused by this force about the line CD. \$5029 Z '9“ I'MU' we” 29%? \$433.53.? +2£Z25J¥¥m37§ % k 67 C7 -)33.é3 135?? 2:3 4947;? if}: dwawj‘ .— Mice/k M v if; fr; 3 5;¢..757- M54049 EGM 2511 Exam 1 Fall 200’ NAME (Last, First) Section: 1592 or 1593 or 1594 (circle one) sorting no: 0 SHOW YOUR WORK - BOX 0R UNDERLINE ANSWERS -— FEDS REQUIRED FOR EQUILIBRIUM PROBLEMS Tab Problem 3. (Wpts) The bent rod ABCD is supported by the beating at A and by the cable DE. Rod ABCD can slide freely in the y direction at the hearing, but the bearing prevents rotation about the x and z axes as well as preventing translation in the x and 2. directions. The moment vector of the applied couple - at B is parallel to the z axis and the 27 lb. applied force at C is straight down in the —y direction. a) By analyzing rod ABCD, determine the required force in cable DE to maintain equilibrium. b) Calculate the magnitude of the force P (which is parallel to z direction). 0) Find all the support reaction components (forces m couples) acting at A. 4 ft ; A; _ ‘ DE <1 44 2 lb ﬂag-"H so ? . _ A; Md It ‘3. I'fn—I-f‘ CAI— ”"- ,H “1/ // “"14 -__...--" p D A A \ DE = #82 + 43‘ —. 3.5%, 1315:7495 .5ftA a 75£=7B£ if +‘iam3’ié x 9-5-55 ?-é05 ?-g.i:.“§ J a) 2;“ = H27 4won 7;; :0 J 735 354:??? I}: #8,”? i595 .ﬂw 4m 2:5{ﬁ;5>64,931f._7>[5):0 ‘ knew? % {331113- c.) 2 My: "CA2, +50 - 2W?) 4- if»! Jtééémltk :30 25% : 5003,34 r-P ) w gr: Ax .—_‘«:5__, (wt-3:24 :5: A :2: x we; ’ X 2’3st #5,“ + if, (Maﬁa; :5)" a“: éZiJ/AJﬁ 9.595 F"? : ,4;E + 54.30% ~§§§3mmq> :0) A; = WM? 2*:— 97.2% ' (oHufr wan) ...
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EXAM011 - EGM 2511 Exam 1 Fall 200’ NAME(Last First g ‘...

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