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Unformatted text preview: EGM 2511 Exam 1 Spring 2008 NAME (Last, First) Section: 1576 or 1578 (circle one) g 110: 0
SHOW YOUR WORK » BOX 0R UNDERLINE ANSWERS  FBDs REQUIRED FOR EQUILIBRIUM PROBLEMS Problem 1. (33 points total)
a) Suppose the 600 1b force below is resolved into two components, one in the aa’ direction and
one in the 1343’ direction. Use trigonometry to find the required magnitudes of these two components. Show any necessary diagrams.
component in a—a’= a Q ’1' :
component in bb’: is E H: , JQWJSMLS: I
.0 £522, a, camP““‘ ) camp he”: 9493.5977219.
é? suit 38" 5:391:12" @029. a. cam be)” MMPL—L':‘t37.zsoglb,' a) ' Fora particular V‘eaor', "maﬁaEFQE’Bt‘tﬁE'Eii'iEEEi‘SHEBREE; 5336;"; ii {an 655%,"; L69.
Therefore, the square of the direction cosine for 83, cos233= I 2:0 and 83: 6 3' '9 . .7! 4—:07 +C¢52923 1) £95"9e.= oZO ) 535 = cars"(5): 53.5”? c) The product of a scalar and a vector is a vector. @ FALSE (circle one)
d.) The addition of vectors is not commutative. TRUE / (circle one)
e.) Vector products (cross products) are commutative. TRUE /(circle one) f.) The scalar product A'B is equal to the projection of A on B. TRUE 1 (circle one) g.) As far as its rotation and translation effects are concerned, a force acting on an
extended rigid body is best represe nted a e
1) bound vector, 2) free vector, 4) zero vector (circle one) h.) Find the magnitude of the unit vector RAB in the direction between point A (x = 0, y = 3, z = 4)
and point B (X :12, y = 0, z = ~5). 3km; = :* EGM 2511 Exam 1 Spring 2008 NAME (Last, First) Section: 1576 or 1578 (circle one)
SHOW YOUR WORK  BOX 0R UNDERLINE ANSWERJS — FBDs REQUIRED FOR EQUILIBRIUM PROBLEMS Problem 2. (33 points total) The rectangular platform is hinged at A and B and is supported by a cable
that passes Over a frictionless hook at E. Knowing that the tension in the cable is 1349 N,
a) Determine the moment component about each of the x, y and z coordinate axes caused by the
force exerted by the cable at D. (Give the magnitudes of MX, MY and M2 individually)
b) Find the turning tendency about the line 0F caused by the force exerted by the cable at D. y 0.90m 5;.) 1:09 = 3.2,: +235]?D .3. A A A '
DE = a 2:30.» +5503 445k), bE—3,55 ‘23" _'__ __ I 3;? Igpﬁ 5 A
F i DE 355" 3.553 3,55 FEE = 37¥j£+5795‘ 4'55): N A "k k
_.__ a.
ﬁg: rm: 3‘ FitDE : A a
03.2. 2:25
X AW 570 #855 ﬁg, ... 42.32.53" 4» 7915.; ﬂaw3 NW
‘ ' .7: s {VIM ’0 Mx: 4:293 KMM ) Mg: 779 Nﬁ”; Mi! lgﬁgzﬁf
b.) t" 3.2,: 4— 1.93 ) 093.7221; ? 3W: 0:859352 +0.5W5‘fg
.4 AAsz 19:9
MW: 4:0275 + 363244 : 49%? e: r7E—Nm/l A “I A
My .: @5735; + .5:w¢a~).(;2ez.5.:+ M53 Hawk ). EGM 2511 Exam 1 Spring 2008 NAME (Last, First) Section: 15% or 1578 (circle one)
SHOW YOUR WORK  BOX 0R UNDERLINE ANSWERS — FBDs REQUIRED FOR EQUILIBRIUM PROBLEMS Problem 3. (34 points total) The lever PQ is welded to the bent rod QSTU which is supported by a single
thrust bearing at S and by the rigid link UV. Link UV is in a plane parallel to the yz plane (it has no x
Component) and has ballandsocker connections at each end. Neglect the weights of QSTU, the lever PQ
and the link UV. a) Determine the magnitude of the force in UV.
13) Find the five support reaction components at S, where the rod is supported by the bearing. AC) a.) £54 : éOOégQDwf/BUV “GOD‘SO 5 UV: Jzﬁgumjmﬁtgm/ . _ ._ 22 _ . __ b) 2F — 53 +T?(12#9)._03 55 1152 M M m52 kA/
£Fx= “5x +é00N=03 6%.: 493321! 29—}: as; + érzzasjro, sax 430M )3
EMx : Cx — e‘é’ﬁz‘fﬁ’lOSﬁo Cy: 24m m
I 13 J "———“...'=‘:"':""
iMz ~ C: + 1302mm.— $00 («299:0 cz=—‘?Az AM
’3 ) W. (pPPpét'lle AS 5 2W”) ”) ...
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This note was uploaded on 10/24/2010 for the course EGM 2511 taught by Professor Jenkins during the Fall '08 term at University of Florida.
 Fall '08
 Jenkins
 Statics

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