exam111 - EGM 2511 Exam 1 Spring 2008 NAME(Last First...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: EGM 2511 Exam 1 Spring 2008 NAME (Last, First) Section: 1576 or 1578 (circle one) g 110: 0 SHOW YOUR WORK » BOX 0R UNDERLINE ANSWERS - FBDs REQUIRED FOR EQUILIBRIUM PROBLEMS Problem 1. (33 points total) a) Suppose the 600 1b force below is resolved into two components, one in the a-a’ direction and one in the 1343’ direction. Use trigonometry to find the required magnitudes of these two components. Show any necessary diagrams. component in a—a’= a Q ’1' : component in b-b’: is E H: , JQWJSMLS: I .0 £522, a, camP““‘ ) camp he”: 9493.5977219. é? suit 38" 5:391:12" @029. a. cam be)” MMPL—L':‘t37.zsoglb,' a) ' Fora particular V‘eaor', "mafiaEFQE’Bt‘tfiE'Eii'iEEEi‘SHEBREE; 5336;"; ii {an 655%,"; L69. Therefore, the square of the direction cosine for 83, cos233= I 2:0 and 83: 6 3' '9 . .7! 4—:07 +C¢52923 1) £95"9e.= oZO ) 535 = cars-"(5): 53.5”? c) The product of a scalar and a vector is a vector. @ FALSE (circle one) d.) The addition of vectors is not commutative. TRUE / (circle one) e.) Vector products (cross products) are commutative. TRUE /(circle one) f.) The scalar product A'B is equal to the projection of A on B. TRUE 1 (circle one) g.) As far as its rotation and translation effects are concerned, a force acting on an extended rigid body is best represe nted a e 1) bound vector, 2) free vector, 4) zero vector (circle one) h.) Find the magnitude of the unit vector RAB in the direction between point A (x = 0, y = 3, z = 4) and point B (X :12, y = 0, z = ~5). 3km; = -:* EGM 2511 Exam 1 Spring 2008 NAME (Last, First) Section: 1576 or 1578 (circle one) SHOW YOUR WORK - BOX 0R UNDERLINE ANSWERJS — FBDs REQUIRED FOR EQUILIBRIUM PROBLEMS Problem 2. (33 points total) The rectangular platform is hinged at A and B and is supported by a cable that passes Over a frictionless hook at E. Knowing that the tension in the cable is 1349 N, a) Determine the moment component about each of the x, y and z coordinate axes caused by the force exerted by the cable at D. (Give the magnitudes of MX, MY and M2 individually) b) Find the turning tendency about the line 0F caused by the force exerted by the cable at D. y 0.90m 5;.) 1:09 = 3.2,: +235]?D .3. A A A ' DE = a 2:30.» +5503 445k), bE—3,55 ‘23-" _'__ __ I 3;? Igpfi 5 A F i DE 355" 3.553 3,55 FEE = -37¥j£+5795‘ 4'55): N A "k k _.__ a. fig: rm: 3‘ Fit-DE : A a 03.2.- 2:25 X AW 570 #855 fig, .-.-.- 42.32.53" 4» 7915.; flaw-3 NW ‘ ' .7: s {VIM ’0 Mx: 4:293 KMM ) Mg: 779 Nfi”; Mi!- lgfigzfif b.) t" 3.2,: 4— 1.93 ) 093.7221; ? 3W: 0:859352 +0.5W5‘fg .4 AAsz 19:9 MW: 4:02-75 +- 363244 : 49%? e: r7E—Nm/l A “I A My .-: @5735; + .5:w¢a~).(;2ez.5.:+ M53 Hawk ). EGM 2511 Exam 1 Spring 2008 NAME (Last, First) Section: 15% or 1578 (circle one) SHOW YOUR WORK - BOX 0R UNDERLINE ANSWERS — FBDs REQUIRED FOR EQUILIBRIUM PROBLEMS Problem 3. (34 points total) The lever PQ is welded to the bent rod QSTU which is supported by a single thrust bearing at S and by the rigid link UV. Link UV is in a plane parallel to the yz plane (it has no x Component) and has ball-and-socker connections at each end. Neglect the weights of QSTU, the lever PQ and the link UV. a) Determine the magnitude of the force in UV. 13) Find the five support reaction components at S, where the rod is supported by the bearing. AC) a.) £54 : éOOégQDwf/BUV “GOD‘SO 5 UV: Jzfigumjmfitgm/ . _ ._ 22 _ . __ b) 2F -— 53 +T?(12#9)._03 55 -1152 M M m52 kA/ £Fx= “5x +é00N=03 6%.:- 493321! 29—}: as; + érzzasjro, sax 430M )3 EMx : Cx — e‘é’fiz‘ffi’lOSfio Cy: 24m m I 13 J "——-—“...'=‘:"':"" iMz ~ C: + 1302mm.— $00 («299:0 cz=—‘?Az AM ’3 ) W. (pPPpét'lle AS 5 2W”) ”) ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern