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HW 10 Prob 3_90

# HW 10 Prob 3_90 - PROBLEM 3.90 Three control rods attached...

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Unformatted text preview: PROBLEM 3.90 Three control rods attached to a lever ABC exert on it the forces shown. (a) Replace the three forces with an equivalent force-couple system at B. (b) Determine the single force that is equivalent to the force-couple system obtained in Part a, and specify its point of application on the lever. SOLUTION A (a) First note that the two 20—lb forces formA couple. Then “x; g F = 48 lb 41 6 {55° where 9 = 180° —— (60° + 55°) = 65° and M = 2MB = (30 in.)(48 lb) cos 55° ~ (70 in.)(20 lb) cos 20° = —489.62 lb - in The equivalent force-couple system at B is F=48.0 lb 465° ’ M=4901b~in.)< (b) The single equivalent force F' is equal to F. Further, since the sense of M is clockwise, F’ must be applied between A and B. For equivalence. 2MB: M=-—aF’cos 55° Where a is the distance from B to the point of application of F’. Then —489.62 lb - in. = ~a(48.0 lb) cos 55° or a=l7.78 in. F’=48.0 lb A650" 4 and is applied to the lever 17.78 in. V To the left of pin B ‘ , 4 ...
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