IB Question 7

IB Question 7 - S of phenol C 6 H 5 OH(s at 298 K is −385 J K −1 mol −1 Calculate the standard free energy change of formation ∆ G of

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Review Question # 7 Name: David Tsai Here is a sample question on the subject of Energetics from a previous IB Test. 1. The standard enthalpy change for the combustion of phenol, C 6 H 5 OH(s), is −3050 kJ mol −1 at 298 K. (a) Write an equation for the complete combustion of phenol. 2C6H5OH+7O2 ->6 CO2+3H2O (1) (b) The standard enthalpy changes of formation of carbon dioxide, CO 2 (g), and of water, H 2 O(l), are −394 kJ mol −1 and −286 kJ mol −1 respectively. Calculate the standard enthalpy change of formation of phenol, C 6 H 5 OH(s). -6272 kJ/mol (3) (c) The standard entropy change of formation, ∆
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Unformatted text preview: S ο , of phenol, C 6 H 5 OH(s) at 298 K is −385 J K −1 mol −1 . Calculate the standard free energy change of formation, ∆ G ο , of phenol at 298 K.-6272 kJ/mol (3) (d) Determine whether the reaction is spontaneous at 298 K, and give a reason. No; Since the temperature does not change, it is not spontaneous. (2) (e) Predict the effect, if any, of an increase in temperature on the spontaneity of this reaction. An increase in temperature will make the reaction spontaneously occur. (2) (Total 11 marks) MNHS – IB HL Chemsitry 1...
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This document was uploaded on 10/22/2010.

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