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# Doc1 - Volume ofthe copper coated on each board =(area...

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Unformatted text preview: Volume ofthe copper coated on each board = (area ofthe board )(thickness) = [8.0x160 cm2)|:0.60 mm) =[8.U><16.0 cm2)|:0.60><10'1cm) =- For 10,000 plates volume ofcopper coated = T.68><l0,000 cm3 2 7".68Xl04cm3 Mass of copper =(densit3r)(volume ) =(8.96)[?.68x104) = 68.81x10‘ g Amount of copper removed (chemical etching) = [80%)[6881X104 g) = 55.0502 x104 g Mass Atomic mass _ 55.I:J5I:32><1I:J4 63.546 2 0.866x104 Moles Moles ofcopper removed = From the reaction Cu [NI-EL C12 |:aq)+~41\11-I3 [aq)+Cu [5:] a 2Cu [NI-EL Cl [adj For 1 mole Cu etching, 1 mole Cu [NI-I3)1 Cl2 is needed. Mass of Cu [NI-I3 :14 Clgneeded = (moles )(molar mass) moles = 0866+4 [17) + 2(3545) = 63.546+68+?0.9 = 202.446 gfmol Mass of (3110515311 Clgrequired = [202.446)[0.866x104) =1?5.31x1o" g =- of (314511413)4 <312 Similarly from the reaction for 1 mole Cu, 4 moles off-‘meonia is required. For etching of 0.866 ><l0'1 moles of Cu , 4 x 0.866X104moles ofNI-Ig is required. Mass ofAmmonia required = Moles )(molar mas s) =[4xo.sssxio*)[17) =5sssx1o" ...
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