Physics131_L10WI10

Physics131_L10WI10 - Physics 131 - Mechanics Le cture10 Fe...

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Physics 131 - Mechanics Lecture 10 February 1, 2010 Homeyra Sadaghiani
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October 24, 2010 Physics 131 - Lecture 10 Announcements HW#4 is due at 9 a.m. on Wed, February 3 r
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Week Date L# Lecture topic Text reading HW 5 1-Feb 10 Equilibrium, using the 2nd Law   3-Feb 11 2nd Law Application: Friction, Drag   6 8-Feb 13 Uniform circular motion 8.1-7 (18 P)   10-Feb 14 Momentum, Impulse & conservation of momentum 9.1-3 (13 P) HW#5   12-Feb F1 Conservation of momentum Tutorial 7 15-Feb H2 Holiday (Presidents' Day)   17-Feb 16 Inelastic collisions 9.4-6 (12 P) HW#6   19-Feb 16 Energy 10.1-4 (13 P) 8 22-Feb 17 Potential energy and elastic collision 10.5-7 (13 P) 24-Feb 18 Work & kinetic energy 11.1-3 (10 P) HW#3 26-Feb E2 EXAM 2- Chapters 5-9 October 24, 2010 Physics 131 - Lecture 10 Lecture Schedule We are here!
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October 24, 2010 Physics 131 - Lecture 10 Example: Unloading A Truck
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October 24, 2010 Physics 131 - Lecture 10 Example: Picture Hanging
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October 24, 2010 Physics 131 - Lecture 10 Example: Weighing Yourself in an Elevator Elevator accelerating upward
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October 24, 2010 Physics 131 - Lecture 10 Example: Static Equilibrium ( F net ) x = ( F i ) x = m r a x = 0 å ( F net ) y = ( F i ) y = m r a y = 0 å
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October 24, 2010 Physics 131 - Lecture 10 Example: Dynamic Equilibrium ( F net ) x = ( F i ) x = m r a x = 0 å ( F net ) y = ( F i ) y = m r a y = 0 å
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October 24, 2010 Physics 131 - Lecture 10 A spaceship is approaching the surface. It is slowing its moving downward by firing its rocket motor. Which is the correct free-body diagram for the spacship? Clicker Question
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A fish is being yanked upward out of the water using a fishing line that breaks when the tension reaches 180 N . The string snaps when the acceleration of the fish is observed to be is 12.2 m/s 2 . What is the mass of the fish? (a) 14.8 kg (b) 18.4 kg (c) 8.2 kg m = ? a = 12.2 m/s 2 snap ! October 24, 2010 Physics 131 - Lecture 10 Clicker Question
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Force and acceleration a = 12.2 m/s 2 snap ! Draw a Free Body Diagram!! m = ? Use Newton’s 2nd law in the upward direction: F TOT = m a T - mg = m a T = m a + mg = m( g + a ) m T g a = + ( 29 kg 2 8 s m 2 12 8 9 N 180 m 2 . . . = + = T mg October 24, 2010 Physics 131 - Lecture 10
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Man A (70kg) and Man B (90kg) are hanging motionless from a roof. What is the tension, T A , in the top rope? (Assume the ropes are massless and use g = 10 m/s 2 .) T A T B Man A: 70 kg Man B: 90 kg 10050008v2_1 A. 200 N B. 700 N C. 900 N D. 1600 N E. None of the Above Clicker Question October 24, 2010 Physics 131 - Lecture 10
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If you cut the rope between Man A and Man B so that Man A stays motionless, what is the tension, T A , in the top rope? (Assume the ropes are massless and use g = 10 m/s 2 .) A. 0 N B. 200 N C. 700 N D. 900 N E. 1600 N Man B: 90 kg T A Man A: 70 kg 10050008v3_2 Clicker Question October 24, 2010 Physics 131 - Lecture 10
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If you cut the rope between Man A and the roof, what is the tension, T B , in the bottom rope? (Assume the ropes are massless and use g = 10 m/s 2 .) A. 0 N B. 200 N C. 700 N D. 900 N E. 1600 N T B Man A: 70 kg Man B: 90 kg 10050008v2_3 Clicker Question October 24, 2010 Physics 131 - Lecture 10
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Man A (70kg) and Man B (90kg) are hanging motionless from a platform at rest. What is the tension, T A , in the top rope if the platform accelerates upward at a constant rate of 2 m/s 2 ? (Assume the ropes and platform are massless and use g = 10 m/s 2 .) T A T B Man A: 70 kg Man B: 90 kg A. 0 N B. 1280 N C. 1600 N D.
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This note was uploaded on 10/24/2010 for the course PHY PHYSICS 13 taught by Professor Mylander during the Spring '09 term at Cal Poly Pomona.

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Physics131_L10WI10 - Physics 131 - Mechanics Le cture10 Fe...

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